
Home  Forums  Rules  Articles  The diyAudio Store  Gallery  Blogs  Register  Donations  FAQ  Calendar  Search  Today's Posts  Mark Forums Read  Search 
Solid State Talk all about solid state amplification. 

Please consider donating to help us continue to serve you.
Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving 

Thread Tools  Search this Thread 
16th July 2013, 03:22 AM  #21 
diyAudio Member
Join Date: Aug 2012
Location: pasuruan

controversial power from Lamongan Indonesia

17th July 2013, 12:14 PM  #22  
diyAudio Member
Join Date: Mar 2009
Location: Buenos Aires  Argentina

Quote:
You should edit that to: Quote:
I guess "1000W" is the magic label 

18th July 2013, 09:47 PM  #23  
diyAudio Member
Join Date: Nov 2009
Location: Kudus, Malang, Dieng

Quote:
Also that TIP won't work at high voltages. I found this sch http://s19.postimg.org/jk0y7uf5f/Namec_sch.png 

22nd July 2013, 07:47 PM  #24 
diyAudio Member
Join Date: Jun 2013
Location: lamongan

how to get out 1000wat?
no draw bias. 45Vac 1000wat how do you calculate it? 
29th July 2013, 12:43 AM  #25  
diyAudio Member
Join Date: Dec 2011

Quote:
ocl+pioner+pa+010.jpg 

29th July 2013, 02:16 AM  #26  
diyAudio Member

Quote:
Subtract 3 Volts for worstcase rectifier drop. Gives 60.64 Volts peak. Assume 6 Volts (just a guess) for minimum voltage between power rail and output, Vclip, across amplifier. So peak rail voltage, Vrailpk, is assumed to be 60.64 Volts. You cannot get 1000 Watts RMS into 2 Ohms or more, with that rail voltage. But you could get 1000 Watts RMS into 1 Ohm: Voutpk = √(2(P_rms)(Rload)) For 1000 W RMS into 1 Ohm: Voutpk = √(2(1000)(1)) = 44.72 Volts Peak Vout_RMS = 31.62 Volts The minimum reservoir capacitance would be: Cmin (in uF) = 1000000(Vpk/(Rload(VrailVclipVpk)))( (1/(2 fmains)) + (0.02/Voltage_Rating) ) Cmin (in uF) = 1000000(44.72/(1(60.64644.72)))( (1/(2x50)) + (0.02/63) ) Cmin = 46520 uF I would recommend using qty 10 x 4700 uF, at a minimum. If you used 100000 uF, then the max rated RMS output power would be 1226 Watts, because the max clipping voltage would be lower, so the rated max peak output voltage could be higher.  For higherimpedance speakers: Voutpk = √(2(P_rms)(Rload)) Voutpk for 1000W RMS into 8 Ohms would be 126.4 V peak. You would have to add Vripple, Vclip, and Vdiodes to that, to get the needed transformer output voltage. The peak current would be 15.8 amps. So maybe add 15 Volts, giving 141 V pk, or 100 V RMS transformer output. The good news is that it would only need about 22000 uF per rail. Voutpk for 1000W RMS into 4 Ohms would be 89.4 V peak. You would have to add Vripple, Vclip, and Vdiodes to that, to get the needed transformer output voltage. The peak output current would be 22.4 amps. So maybe add 15 Volts, giving 104.4 V pk, or 74 V RMS transformer output. The good news is that it would only need about 25200 uF per rail (but 47000 uF would get the ripple down to 5%). 

29th July 2013, 02:23 AM  #27 
diyAudio Member
Join Date: Sep 2010
Location: Depok, West of Java

Many amp. kits from Indonesia claimed more power than it's should be. They can not distinguish about RMS power and PMPO power or they did not care. I doubt they even measure their designs. It is shame .

29th July 2013, 02:30 AM  #28 
diyAudio Member
Join Date: Sep 2010
Location: Depok, West of Java


29th July 2013, 03:07 AM  #29 
diyAudio Member
Join Date: Aug 2011


29th July 2013, 04:17 AM  #30  
diyAudio Member

Correction:
Quote:


Thread Tools  Search this Thread 


Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
1000 Watt LM3886 Or TDA?  binsky3333  Chip Amps  39  26th August 2012 04:37 PM 
1000 watt amplifiers  boxcustom  Car Audio  32  31st May 2011 04:49 PM 
F/S 1000 watt sub amps (4) units only  rubicon  Swap Meet  10  31st December 2010 05:37 PM 
1000 watt Amp Modules  Zero Cool  Class D  24  29th September 2008 08:32 PM 
1000 Watt with usb input !  cph2000  Class D  1  4th October 2007 06:04 AM 
New To Site?  Need Help? 