Vs= ±70V, Load=4Ω
circuit
Q: Why the power curve was parabolic?
i.e. low and high output voltage has low dissipation.
An externally hosted image should be here but it was not working when we last tested it.
circuit
An externally hosted image should be here but it was not working when we last tested it.
Q: Why the power curve was parabolic?
i.e. low and high output voltage has low dissipation.
Last edited:
@Ian : I've change the image now. thanks.
@Andrew :
the LTspice formula to express Transistor Q1 dissipatioan is as follow:
V(Vcc,out)*Ic(Q1) + V(Vin,out)*Ib(Q1)
what is V(Vcc,out)? is that mean V(Vsupply-Vout)?
if I want to calculate power dissipation at output=10V,
then it would be :
V(70-10)*2.5A = 150W + V(Vin,out)*Ib(Q1) [which is low enough]
that should be correct, right?
@Andrew :
the LTspice formula to express Transistor Q1 dissipatioan is as follow:
V(Vcc,out)*Ic(Q1) + V(Vin,out)*Ib(Q1)
what is V(Vcc,out)? is that mean V(Vsupply-Vout)?
if I want to calculate power dissipation at output=10V,
then it would be :
V(70-10)*2.5A = 150W + V(Vin,out)*Ib(Q1) [which is low enough]
that should be correct, right?
This appears to be a DC calculation. Fine for a servo mechanism, but for an audio amplifier you need to do an AC calculation and average over a complete cycle. To do this properly involves some simple calculus.kroto said:if I want to calculate power dissipation at output=10V,
then it would be :
V(70-10)*2.5A = 150W + V(Vin,out)*Ib(Q1) [which is low enough]
Now throw in driving a reactive load like a speaker where the voltage is out of phase with the current. There will be situations where most of the voltage is across the transistor and most of the current flows at the same time. Once the instantaneous die temperature gets to critical it's sayonara! And for BJT's there is secondary breakdown.......
- Status
- This old topic is closed. If you want to reopen this topic, contact a moderator using the "Report Post" button.
- Home
- Amplifiers
- Solid State
- Understanding Class-B Tr Dissipation graph