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 14th November 2012, 09:31 PM #1 diyAudio Member   Join Date: Feb 2012 Please help me understand the voltage regulator with external bypass BJT? Such as this schematic: I understand that at low currents the BJT is off and the current is supplied by the voltage regular, then as the current increases a I*R vbe develops on Q1, until the point of Vbe(on) then Q1 starts to conduct. My question is, how is the feedback maintained to provide constant output voltage? I don't quite understand the feedback path. Vbe should adjust with the load current, but is the current path through the load straight from Vdc to vout to Q1 or is R1 somehow in the path?
 14th November 2012, 09:32 PM #2 diyAudio Member   Join Date: Feb 2012 Also, how does the performance change when R2 is removed? I seen this circuit both with and without R2.
 14th November 2012, 10:26 PM #3 diyAudio Member     Join Date: Dec 2005 Location: the north R2 is a base stopper for the big transistor. It is there for to make the input to the transistor suitable. It might work without R2, but we can say R2 is there for safety. If you look into schematics of power amplifiers, you can see these Base stopper resistors. They are in small value. 2.2, 4.7 or 10 Ohm. __________________ lineup
diyAudio Member

Join Date: Jul 2003
Location: Bath, UK
Quote:
 how is the feedback maintained to provide constant output voltage? I don't quite understand the feedback path
It's very simple: look at the current paths.

if output voltage drops due to loading, the regulator tries to maintain the voltage output and that requires it supplies more current into the output. That current must be reflected in the input current to your '7812' input; which increases the voltage across R1 and therefore, Q1 is driven harder.

In effect the expected voltage drop across R1 due to variations in load current is divided by the hfe of the pass transistor.

Q1 remains under control of the 3-pin reg unless cut-off when current through R1 drops low enough that V across r1 <0.6v.

diyAudio Member

Join Date: Feb 2006
Location: Ashland,Ky U.S
I'm sorry to inform you but that schematic and its intended use are incorrect. The circuit in post 1 is a short circuit protection scheme and should not be used as a "current boosted regulator" , for one it will inject all the noise and ripple from the input straight into the output, making the whole point of using a regulator moot, unless you simply want a voltage and dont care if its clean.
Attached is the correct way. Note c1 and c2 are solid tantalum types and should be included with these types of regulators.
Attached Images
 ScreenHunter_03 Nov. 14 19.47.jpg (11.6 KB, 130 views)

Last edited by jerluwoo; 14th November 2012 at 11:47 PM.

 15th November 2012, 12:06 AM #6 diyAudio Member   Join Date: Jul 2003 Location: Bath, UK Not true at all. Q1 remains under the control of the reg; worst case, the base is driven by the input filtered by R1/C1. The output is quiet! PS conventional 3-pin regs don't actually need an output cap for stabilty, although it helps output load transient response. LDO regs however usually do require the output cap for stability since it forms part of the reg's compensation. An input cap is always necessaary though regardless of type. Last edited by martin clark; 15th November 2012 at 12:12 AM.
 15th November 2012, 02:19 AM #7 diyAudio Member     Join Date: Feb 2006 Location: Ashland,Ky U.S It is R1/C1 which turns Q1 into a common base amplifier, with ripple fed into the emitter and none at the base giving some gain to the ripple. Last edited by jerluwoo; 15th November 2012 at 02:32 AM.
 15th November 2012, 03:50 AM #8 diyAudio Member   Join Date: Jul 2003 Location: Dona paula, Goa One thing is sure... It will have poor load regulation. Gajanan Phadte
 15th November 2012, 04:11 AM #9 diyAudio Member   Join Date: Nov 2009 Location: algeria/france Load sensitivity of the schematic post 1 will be the one of the regulator since the transistor is enclosed in a feedback loop while the second schematic will have poor loading stability , the transistor and current limiting resistors being outside of the loop.
 15th November 2012, 06:53 AM #10 diyAudio Member     Join Date: Nov 2005 Location: San Antonio For me, the first pic is the configuration usually associated with the 3-terminal regs. The 2nd pic I usually associate with the uA723 reg. The configurations seem to be somewhat interchangeable. The feedback network within the 78xx remains functional. If Vout is reduced, that also reduces current through R1. That's my fingers-crossed take on it. __________________ It is error only, and not truth, that shrinks from enquiry. - Thomas Paine

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