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#1231 |
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diyAudio Member
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Christophe i never will look inside tour rack if you promise me to never balme my poor electronic background........
![]() Marc
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website : http://audiyofield.wifeo.com/index.php |
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#1232 |
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diyAudio Member
Join Date: Jul 2011
Location: France
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Several remarks about your reaction. (All out of topic)
- We are living in a kind of middle age, where > 90% of people using equipments don't have the slightest idea of the way they work. From cars to freezers, including mobile phones. Magic everywhere. So the ones who have a mind opened enough to try to understand them just deserve respect. And the ones who build their own ones just deserve admiration. - I was very impressed, when young, by the culture of my parents. Old, i realize it is just a gift of the life, day after day, in response to our curiosity, no such a merit. - The less we can do at the end of our life is to share what the life had shared with us. - By the way, my doctor never blame-me for my poor medical background, comparing to him. On the contrary, he looks impressed by the few things i know in that domain. |
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#1233 | |
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diyAudio Member
Join Date: Mar 2005
Location: Sydney - Australia
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Quote:
Also do you connect a 47R resistor from the SK75 heatsinks to ground or am I reading the circuit incorrectly. Thanks. |
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#1234 |
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diyAudio Member
Join Date: Sep 2007
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Hi Harry3
TL431 from Mouser is OK. Yes these two heatsinks located on PCB are connected to GND via 47 ohm resistor, thus forming serial RC filter from cascode BJT's collector to GND, rather than just C to GND.
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#1235 |
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diyAudio Member
Join Date: Mar 2005
Location: Sydney - Australia
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Hi LC,
thanks for the answers above. Is the TSSA BIGBT HP Amp your best amp so far? What is the wattage at 55Vdc as I need over 150W into 4ohm speakers. How does it compare to the SAA Low Impedance HP amp? Best regards Harry |
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#1236 | |
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diyAudio Member
Join Date: Jul 2011
Location: France
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Quote:
Use the Ohm law to know by yourself the power capability. (It is better to provide tools than food to somebody suffering of salvation) P= VČ/R and V=RI, knowing that Vpeak = Vrms x 1.44. So simple. You just have to subtract the V loss in the emitter resistance and around 3V (Collector–Emitter Saturation Voltage) in the power transistor to get the available peak voltage on your Hp terminal. And to remember that doubling the power only increase the listening level by 3db. Well ..150W only need +-35V peak (=24Vrms) under 4Ohm and 8.75A. Loss in the emitter resistance will be 8.75x 0.22 -> ~2V and 3V loss in transistor -> 40V So, this amp with +-55V will overkill your requirements. By the way, L.C, it would be interesting that you explain to readers the principle of your nice very symmetrical complementary power transistors arrangement. Last edited by Esperado; 6th October 2012 at 12:49 PM. |
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#1237 |
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diyAudio Member
Join Date: Mar 2005
Location: Sydney - Australia
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Hi,
thanks -I am aware of the formulas etc What I do not understand is how the output transistors work in this circuit and how to work out the SOA for the transistors. |
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#1238 | |
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diyAudio Member
Join Date: Jul 2011
Location: France
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Quote:
Give-me 5 minutes, and i will try to explain this ultimatly elegant power output stage. Last edited by Esperado; 6th October 2012 at 03:14 PM. |
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#1239 |
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diyAudio Member
Join Date: Jul 2011
Location: France
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On each branch (+ and -) of the output stage are paralleled NPN and PNP power transistors.
MUR460 and MJL132A. Each one has a resistor emitter (R32, R29, R13, R15) of 0.22 Ohms. Let-us concentrate on the upper (+V) part. When no voltage is applied to the gate of the IRF6110, this one has infinite resistance between Drain and Source. MUL132A base is at the +V potential via R32, so, it does not conduct. MUR460 base is at the HP potential via R40, so, it does not conduct. Let see whats happens when we apply some V at the IRF6110 gate. His DRAIN-SOURCE impedance will decrease. So, the V at the base of the MJL132A will decrease, and, if emitter to base is more than 0,7V, will begin to conduct. Symmetrically, because R32 and R40 have the same values, Voltage at the base of MUR460 will increase of the same amount, and it will begin to conduct too for the same reason. Those two transistors will be paralleled to drive the current, across their 0.22 Ohms emitter resistance to the HP charge. The ZD zeners are here just to protect the IRF gates. This is absolutely beautiful, because perfectly symmetrical between +V and -V half waves, whatever disparities between NPN and PNP devices. Notice that this idea will be a perfect response if we use some Power output FET devices instead of NPN PNP, to avoid the big problem of the disparity of the capacitive holes between N and P Devices. Clever, clever, so elegant !!!! Like all the L.C. designs. Last edited by Esperado; 6th October 2012 at 03:54 PM. |
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#1240 |
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diyAudio Member
Join Date: Jul 2011
Location: France
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Please, read IRF610 instead of IRF 6110.
My mistake. |
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