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#501 | |||
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diyAudio Member
Join Date: Oct 2011
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Quote:
Quote:
Quote:
Thanks guys!!! How about this? Power Inductors Ind 1uH 3A Radial Leads or Power Inductors RFI COIL 1uH 4A
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This is not reality... Last edited by zxgravediggerxz; 15th May 2012 at 11:52 PM. |
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#502 |
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diyAudio Member
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Too small
, not air core. It will saturate easily. This amp is capable of supplying 20A during a transient easy.
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#503 |
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diyAudio Member
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Magnet Wire
Magnet Wire, Plain Enamel (PE), Solderable, Class 130, 1 lb spool, 16 AWG CONWIRE-16MAG-1.0LB - All Spectrum Electronics Amazon.com: Magnet Wire, Enameled Copper Wire, 1lb Spool, 16 AWG, 0.0524" Diameter, 120' Length (Pack of 1): Industrial & Scientific There are many cheap sources If pressed disassemble this http://www.parts-express.com/wizards...TOKEN=90127471 Do for 1uh.(18 turns,16awg-thickness in 1/2" diameter) Last edited by OnAudio; 16th May 2012 at 02:55 AM. |
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#504 |
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diyAudio Member
Join Date: Oct 2006
Location: Belgium the land of chocolate
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Is there a schematic that matches the component layout,to avoid errors.The part numbering of the scheme isn't the same as the board.
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#505 |
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diyAudio Member
Join Date: Jun 2009
Location: GTMO
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Thanks guys.
Next up is to figure out a heatsink size. Does everything on that edge of the board need to attach to the sink and do they all need to be isolated? This will be my first solid state build. I have done tubes in the past, so this heatsink stuff is all new to me. |
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#506 | |
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diyAudio Member
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Quote:
An air-core inductor cannot saturate, else you will be magnetising air.
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Kindest regards Nico Last edited by Nico Ras; 16th May 2012 at 12:28 PM. |
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#507 | |
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diyAudio Member
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Quote:
U=I*R => I = U/R Imax = 80V / 4 ohm = 20 A. Which in turn means: Pmax = 80 V * 20 A = 1600 W (!!!!!) At 8 ohm load: Imax = 80 V / 8 ohm = 10 A Pmax = 80 V * 10 A = 800 W (!!) @zxgravediggerxz So listen to the experts: Use Air-core
Last edited by nakamoomin; 16th May 2012 at 12:52 PM. Reason: typo |
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#508 |
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diyAudio Member
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According to Mr. Ohm's law P=I^2 x R; therefore P = 20^2 x 8 = 3200 watt, or into 4 Ohms P=1600 watt.
These numbers seems a little Chinese (or Greek as they say) to me. I stand to be corrected, but to store 3200J a 1 Farad Cap is required (since the caps are in series for each 40V rail 200 x 10 000uF caps would do the trick at a cost of around US$1800 at Mouser.)
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Kindest regards Nico |
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#509 | |
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diyAudio Member
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Quote:
But with a +/- 60 V PSU (as suggested in this thread) you can theoretically pull 15 A with an 8 ohm load. That means 15^2*8 = 1800 W (!!!). To get 3200W out of an 8 ohm load you would need to use +/- 80V PSU. ![]() These numbers are what's called PMPO rating (Peak Momentary Power Output) and describe the maximum instantaneous power possible. A lot of "Chinese" manufacturers use this number to inflate their performance instead of using RMS (Root Means Square) rating which says something about continuous power. |
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#510 |
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diyAudio Member
Join Date: Jul 2007
Location: Round Rock, TX
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Can other output transistors be used? I bought some OnSemi BJTs in TO-264 packages that are close in specs. I can't remember PN and I'm at work right now.
Re. the comment about air core inductors, I believe OnAudio was misunderstood and he meant to say the ones suggested at Mouser are not air core and will saturate. He is actually recommending air core type. |
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