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Old 2nd August 2011, 11:39 AM   #1
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Default finding feedback line and gain controlling resistor

The question i'm going to ask is that where is the feedback line in this amplifier and which is the resistor will determine the gain ?
I want to vary the gain for optimum performance, but couldn't find it.

Thanks in advance
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Old 2nd August 2011, 01:29 PM   #2
DF96 is offline DF96  England
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R18 (2k7) is the feedback resistor. Bear in mind that altering feedback doesn't just vary the closed-loop gain, you will also change bandwidth and potentially affect stability.

Or is it R4 (1k). I'm not sure. Maybe both.

This circuit looks like it has had HF stability problems which have been patched up by sprinkling capacitors everywhere.

Last edited by DF96; 2nd August 2011 at 01:32 PM. Reason: extra
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Old 2nd August 2011, 01:43 PM   #3
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df96,
just to be sure, will it destroy my amp or lead to component failure ? or quality reduction ? (permanent changes, that can't be change even after i return to its original value.

Wanted to try to vary these values, see what will happen X.x

my friend said maybe R11 (2k2), and R10 (2k7), but just according to his feeling ^^

Last edited by guitar89; 2nd August 2011 at 01:46 PM.
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Old 2nd August 2011, 02:01 PM   #4
juma is offline juma  Serbia
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Gain (roughly) equals R18 || R4 / R5
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Old 2nd August 2011, 02:10 PM   #5
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Quote:
Originally Posted by juma View Post
Gain (roughly) equals R18 || R4 / R5
what is the ||| you written meant for

hm...... R5 ? seems unrelated ? (well.... i'm a beginner)
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Old 2nd August 2011, 02:27 PM   #6
DF96 is offline DF96  England
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|| means in parallel. I think the answer may be ((R18||R4)/R5)+1, which means calculate the resistance of R18 and R4 in parallel, then divide by R5, then add 1.

Bear in mind that some resistors (possible R4?) have a DC bias effect as well as AC signal. This is quite a complicated circuit so I would not fiddle with it before understanding what each component does.
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Old 2nd August 2011, 02:39 PM   #7
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Quote:
Originally Posted by DF96 View Post
|| means in parallel. I think the answer may be ((R18||R4)/R5)+1, which means calculate the resistance of R18 and R4 in parallel, then divide by R5, then add 1.

Bear in mind that some resistors (possible R4?) have a DC bias effect as well as AC signal. This is quite a complicated circuit so I would not fiddle with it before understanding what each component does.
hm.... the designer of this circuit had mentioned that R2,R12,VR2,VR12 is used to adjust bias and trim DC offset, so means those are not for bias ?

anyway, you mean parallel means by multiplying them ? or what should i do if i want to tweak the gain ?
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Old 2nd August 2011, 02:50 PM   #8
DF96 is offline DF96  England
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Google "resistors in parallel". Almost any resistor in a circuit may have an effect on bias, which is why I suggest you understand the circuit before changing it.
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Old 2nd August 2011, 02:53 PM   #9
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hm..... i'm a beginner, so is there any link you could offer me to read about ? (all details about amplifier circuit ?
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Old 2nd August 2011, 03:55 PM   #10
juma is offline juma  Serbia
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Quote:
Originally Posted by DF96 View Post
...((R18||R4)/R5)+1....
Exactly
That's why I said "roughly"
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