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Old 2nd August 2011, 08:44 AM   #1
robmil is offline robmil  United Kingdom
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Default emitter resistors - how to calculate for discrete opamp.

Hi

I'm looking at building another discrete opamp preamp and while looking at a few designs I have seen quite different emitter resistor values ranging from - 3.9ohms on a bryston design to 33ohms on the JE990 design. Samual Groner
uses anything from 2.7ohms to 18ohms.

Is there a calculation for this resistor, can you scope the difference in values - is there a big difference between say 3ohm, 6ohms and 10ohms in the same circuit? does it make an audible difference going from 30ohms down to a lower value ?

thanks

Rob
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Old 2nd August 2011, 11:12 AM   #2
godfrey is offline godfrey  South Africa
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Emitter resistors where - input stage or output stage or...?
Either way, yes it makes a difference. Have you got a schematic for reference?
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Old 2nd August 2011, 01:35 PM   #3
DF96 is offline DF96  England
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Emitter resistors depend on required stage and total open-loop gain, distortion, quiescent current etc. There isn't a quick answer to your question, except to suggest you read a good book on op-amp internal design.
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Old 2nd August 2011, 06:16 PM   #4
robmil is offline robmil  United Kingdom
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thanks for the replies

It's the output emitter resistors.
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Old 2nd August 2011, 06:21 PM   #5
DF96 is offline DF96  England
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Output emitter resistors help ensure a clean handover between the two halves of the push-pull. The value depends on the circuit used, and affects the correct quiescent current.
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Old 4th August 2011, 02:46 AM   #6
CBS240 is offline CBS240  United States
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Assuming push-pull class AB bias, one place to start might be Zout~= (re+Re)/2.
're' being the intrinsic resistance of the transisor used. There is an audiable effect in that there is an optimum value that results in lower crossover distortion.
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