|
|
|||||||
| Home | Forums | Rules | Articles | Store | Gallery | Blogs | Register | Donations | FAQ | Calendar | Search | Today's Posts | Mark Forums Read | Search |
| Solid State Talk all about solid state amplification. |
|
Please consider donating to help us continue to serve you.
Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving |
|
|
|
Thread Tools | Search this Thread |
|
|
#1 |
|
diyAudio Member
|
Hello,
My knowledge in electronics is limited and I need help. In Bob Cordell’s book on page 49, in the part about “Output stage bias current”, it is noted that, the 2 drivers and the 2 output transistors of Figure 2.12 require at least 4 Vbe voltage drops. In the schematic the Vbe multiplier around Q5 delivers 3.3xVbe ? What am I missing? Thank you (Thank you Bob Cordell for your excellent book.) |
|
|
|
|
#2 |
|
diyAudio Member
Join Date: Dec 2005
Location: the north
|
It is rather normal
3.3 x Vbe can be enough to set a low current in Class AB output stage. For Class A we need more than this.
__________________
lineup |
|
|
|
|
#3 |
|
diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
|
the temp comp value for the semiconductors varies with current.
If the outputs and drivers and Vbe multiplier are all operating at different currents, even if we adopted identical devices for all 5 locations, then we find that precisely 4times is not the correct temp co. If the Vbe does not measure the full range of output or driver temperature change then it will under compensate. More likely the drivers do not change too much and thus the Vbe over compensates for the output devices and a corresponding reduction in Vbe sensitivity to temperature brings the temp co to near what is required by the circuit over a range of operation conditions.
__________________
regards Andrew T. |
|
|
|
|
#4 |
|
diyAudio Member
|
Hello lineup and AndrewT and thank you for your replies.
Bob Cordell uses a 518 Ohms resistor across the base-emitter of the multiplier transistor (R7). He must have done some calculation which I cannot follow. This a not a preferred resistor value. Regards |
|
|
|
|
#5 | |
|
diyAudio Member
Join Date: May 2008
Location: Albany , NY (smallbany)
|
Quote:
That 518R would most likely be 330-470 fixed resistance plus a 500R trimmer (20 turn variable resistor) , in series . Cordell uses a 10ma source for the voltage stage. below 1 is a 8.8ma source. The variables are A. The source current , B. the gain of the Vbe device , and C. the ratio of the B-C to the B-E resistance. 2sc3503 and MJE340 will be on average - a 2.3 to 1 ratio (B-C / B-E - for 50 - 100ma op bias). Observe what the values are between the 8.8ma and 10ma examples below. Real life amps reflect these bias points within a few percent. Both examples set a BJT OP stage to 75-80ma per device. PS - for a real circuit you would start with the 500R trimmer at maximum value (499R OS
__________________
Mongrel website , always current and updated : http://67.248.209.21/D%3A/WEBSITE/ Last edited by ostripper; 21st July 2011 at 09:38 PM. |
|
|
|
|
|
#6 |
|
diyAudio Member
|
Hello ostripper,
thank you very much. Regards |
|
|
| Currently Active Users Viewing This Thread: 1 (0 members and 1 guests) | |
| Thread Tools | Search this Thread |
|
|
|
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Voltage multiplier | argonrepublic | Power Supplies | 27 | 25th February 2010 02:05 PM |
| One-Quadrant Multiplier | Tim__x | Solid State | 4 | 13th October 2006 10:57 AM |
| Vbe Multiplier Help Please | mefistofelez | Solid State | 2 | 6th December 2004 06:14 PM |
| cap multiplier or not? | PederBass | Solid State | 13 | 23rd March 2004 06:26 PM |
| New To Site? | Need Help? |
| Page generated in 0.10032 seconds (67.26% PHP - 32.74% MySQL) with 11 queries |