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Old 11th March 2011, 12:36 PM   #1
Elvee is offline Elvee  Belgium
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Post Halve the diamond, double the performance!!!

Hi,

Here is what is basically a Taylor half-diamond follower, but with a twist: Q4 and Q5 take care of the positive part of the signal, ensuring symetrical performance, and smooth class B operation:
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Old 11th March 2011, 04:06 PM   #2
jam is offline jam  United States
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Holding the input constant what is the worst case oamffset (drift)?
It does look like a novel idea.

Jam
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Old 11th March 2011, 04:41 PM   #3
Elvee is offline Elvee  Belgium
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Quote:
Originally Posted by jam View Post
Holding the input constant what is the worst case oamffset (drift)?
In this example, it is approximately 50mV (Q1 and Q3 held at the same temperature).

It depends on the matching of the current densities in Q1 and Q3. If the currents are scaled in the same proportion as the junction areas, a first order cancellation occurs, both statically and dynamically.
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Old 18th September 2011, 01:59 PM   #4
AKSA is offline AKSA  Australia
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Brilliant, Elvee!

Have you built and auditioned it?

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Old 18th September 2011, 05:20 PM   #5
Elvee is offline Elvee  Belgium
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Quote:
Originally Posted by AKSA View Post
Have you built and auditioned it?
Yes, I have built it, tested it with real audio too: no obvious flaw.
I won't comment further in that direction since I have tin ears, but it sounds OK.

It is not a topology for the faint hearted though: the input impedance is negative, which can be disconcerting to the novice.
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Old 18th September 2011, 11:21 PM   #6
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You know the base current of 2n3055 is wildly not a linear load.
Somehow need to add or subtract that drive current back into
the equation that will hold Q1's emitter drop constant.
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Old 19th September 2011, 12:01 AM   #7
Bigun is offline Bigun  Canada
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I like it !

reminds me a little bit of this: Amplifier Variations.
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Old 19th September 2011, 12:02 AM   #8
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Easier way to hold half diamond emitters at constant voltage drop...
Taylor still worth knowing, please keep exploring the original circuit.
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Old 19th September 2011, 12:52 AM   #9
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Or this way too, could hold those two emitters constant.
You might ask, why not a simple mirror across the top?
Yeah, but a mirror isn't so easy to bootstrap. Or is it???
M2 might want gate swing a few volts above the rail.

I keep trying to throw a gratuitous Taylor in there,
other weird solutions just keep popping in my head.
At least we are watching a collector and bouncing
that info as current to an active load on the emitter...
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Last edited by kenpeter; 19th September 2011 at 01:05 AM.
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