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#1 |
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diyAudio Member
Join Date: Sep 2009
Location: Manchester
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Hello everyone, can someone give me a clue how to calculate the input impedance of the circuit shown? β=100.
Thanks |
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#2 |
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diyAudio Member
Join Date: Apr 2006
Location: Minnesota
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The input resistance of the transistor is Rpi=B/gm, where gm is the transconductance and is given by gm=40*Ic. Ic is the DC collector current.
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#3 |
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diyAudio Member
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Be careful with the units; it is 40 (1/V) in the formula, so if you take Ic in amps, you get Gm in 1/ohm and Rpi in ohm. Milliamps will give you kiloohms, etc. You need to add R1 and R2 in parallel to the input resistance of the transistor to get the input impedance of the circuit.
Last edited by alexcp; 20th January 2011 at 03:26 PM. |
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#4 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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combining those two replies
Input impedance = R1//R2//[Rpi=B/gm] R1=10k seems ultra low in value cf. R2=82k Should there be a term to represent the effect of Re//Rc has on the input impedance? Last edited by AndrewT; 20th January 2011 at 04:00 PM. |
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#5 |
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diyAudio Member
Join Date: May 2007
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Homework?
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#6 |
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diyAudio Moderator
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Looks that way. And fortunately, no one has given a fully correct answer.
hint: the answer is frequency dependent...
__________________
If there's a sucker born every minute, where do the rest of them come from? |
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#7 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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#8 |
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diyAudio Member
Join Date: May 2007
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What about Early effect? That will change the effective value of Rc.
Should we ask whether the OP is looking for a first-year or second-year answer? |
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#9 |
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diyAudio Member
Join Date: Mar 2005
Location: Los Angeles, california
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Zin = R1||R2|| hie.
Art |
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#10 | |
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Banned
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We're only interested in the range where the amplifier is going to be operated, so other than calculating and noting the lower cut-off frequency for all practical purposes the value can be taken as R1||R2||hfe*re.
Quote:
w |
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