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Old 18th December 2010, 01:03 AM   #1
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Default Cascode input question

Hi, is there a the difference between this cascodes input stage?
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File Type: gif cascode2.gif (8.3 KB, 257 views)
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Old 18th December 2010, 01:06 AM   #2
AKSA is offline AKSA  Australia
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Yes, the leftmost schematic holds the cascode at a fixed voltage above GROUND, while the rightmost holds the cascode at a fixed voltage above SIGNAL.

The first runs into overload at very high inputs, and varies the Vce of the input devices. The second has much higher overload, and holds constant Vce on the input devices, eliminating Early effect.

The second is preferable, in my opinion.

Hugh
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Old 3rd February 2011, 03:02 AM   #3
ontoaba is offline ontoaba  Indonesia
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Yes the second, its constant Vce for input transistors increasing its linearity (more precise). Choosing input transistors with constant Vbe at specific current region (look at its Ic-Vbe graph) will result a highest linearity.

Last edited by ontoaba; 3rd February 2011 at 03:05 AM.
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Old 3rd February 2011, 04:54 AM   #4
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The emitter resistors are way too large. They should be less than 100 ohms.
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Old 3rd February 2011, 10:59 AM   #5
ontoaba is offline ontoaba  Indonesia
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Quote:
Originally Posted by sawreyrw View Post
The emitter resistors are way too large. They should be less than 100 ohms.
Where that rules coming from? I am using 470ohm to convert shunt resistor's voltage into current pecisely. 470 is far from that rules.
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Old 3rd February 2011, 11:33 AM   #6
AndrewT is online now AndrewT  Scotland
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Cordell tells us to use the emitter resistors to adjust the gain of the input stage.
He suggests choosing a degeneration value of 10times, but also tells us that this can be any degeneration value.

Some others suggest the Vdrop of Re should be ~half to 100% of Vbe of the input transistors.

Leach shows in detail why he chose 330r in the Lo Tim.

There are lot's of rules. Find the one that suits your compromises. Expect Re from 10r to 1000r.
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Old 3rd February 2011, 12:13 PM   #7
knutn is offline knutn  Norway
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The collector current times the emitter resistance is the max. voltage on the input. 100 ohm emitter resistor and 1 mA collector current tells us that 0.1 V is the maximum you can apply to the stage before clipping. some designers use this to design amplifiers with little TID. Without global feedback the resistors have to be large, and/or the collector current have to be large. I don't think you can apply a rule to the size of the emitter resistors if you don't see it in connection with the collector current.
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Old 3rd February 2011, 12:24 PM   #8
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The amplifier is the End Millennium. Original schematic use 2k.
I do notbuilt the original amp, I only use 3 stages. Sound very good.

I was try using cascode input stage and VAS, just for see any different and I was read this two cascode configuration.

I will try with the second configuration

Now, wich is the Vce "optimus" voltage?

Supose that I use Vcc=25V and Vee=-25. A low Vce value (4,7V) is more desirable that a higher value (12V)?. Or it does not matter? reffering on the input stage.
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Old 3rd February 2011, 12:29 PM   #9
AndrewT is online now AndrewT  Scotland
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you require good performance from the input device.
You look at the options and decide which compromises introduce less distortions/heating/capacitance/unwanted effects.

This may be operating at Vce=2V or at Vce=125V or anywhere in between.

Some designers/builders ear tune to a sweet spot.
I have not heard this so cannot comment on the reliability of finding an accurate sweet spot.
AKSA and Ostripper and others have ear tuned and reported impressive results.
Many very good commercial equipment manufacturers ear tune for popular sound output.
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Last edited by AndrewT; 3rd February 2011 at 12:32 PM.
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Old 3rd February 2011, 12:43 PM   #10
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Thanks for the tip Andrew!
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