Question about wattage of resistance in parallel - diyAudio
 Question about wattage of resistance in parallel
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 22nd November 2010, 03:33 PM #1 diyAudio Member   Join Date: Sep 2010 Question about wattage of resistance in parallel (First off, the question is not about the ohmage, it is about the wattage.) Obviously there is a simple formula to determine resistance in parallel. I need 330 ohms at 2W. I have all one watt resistors. Instead of running a 330ohm 2W resistor, could I run 3 1k 1W resistors in parallel? I figured since the power would be distributed through three 1W resistors the setup would easily handle the 2w that it needs to handle. Is this correct??
 22nd November 2010, 03:40 PM #2 diyAudio Member     Join Date: Sep 2003 Location: Upstate NY Yes, 3 paralleled 1K/1W resistors will give you 333R, at 3W. Dissipation in each resistor is V^2/R, which works even if they are not the same value. Is your actual dissipation 2W or does your schematic call for a 2W resistor? If actually 2W, you probably want to go a bit higher than 3W capability. The usual rule of thumb is to use no more than 1/2 rated power dissipation.
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Join Date: Sep 2010
Quote:
 Originally Posted by BobEllis Yes, 3 paralleled 1K/1W resistors will give you 333R, at 3W. Dissipation in each resistor is V^2/R, which works even if they are not the same value. Is your actual dissipation 2W or does your schematic call for a 2W resistor? If actually 2W, you probably want to go a bit higher than 3W capability. The usual rule of thumb is to use no more than 1/2 rated power dissipation.
Thanks Bob!! Great answer to my question. And thanks for the dissipation pointer also, but yes the schematic calls for 2W so 3W will be plenty!!

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