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#1 |
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diyAudio Member
Join Date: Nov 2009
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Hi people,
As some of you may know I'm currently designing a compressor for my final year project at university. I currently have everything designed and tested on a breadboard. It all works perfectly however there is one quick fix I used that needs sorting before I can design the PCB. The threshold control is simply an op amp in differential configuration. The threshold is controlled via a pot to give a fixed value which is then subtracted from the audio in. This leaves me with the amount of voltage that has crossed the threshold. The problem I have is that as the op amp is dual DC powered - if the audio is below the level of the threshold I get a negative output voltage. This is undesirable as my design requires any audio below the threshold to give an output of 0V. The 'quick fix' around this that was used for testing was to put a diode on the output of the op amp. When the audio is below the threshold, the negative voltage is blocked by the diode. When it is above, the voltage drop across the diode is added back via another pot on a summing amplifier The problem is that obviously the voltage drop across the diode varies for different input levels. Is there a circuit I can implement to make up for the varying voltage drop, or is there another way of blocking the negative voltage from the output? Cheers |
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#2 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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maybe this needs a precision rectifier. An opamp with diodes in the feedback that converts small signal AC to rectified AC ready to be peak sampled or otherwise modified.
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regards Andrew T. |
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#3 | |
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Banned
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Quote:
No, thinking about it you can't exceed the rails on the input. Andrew is right, a half-wave precision rectifier... w Last edited by wakibaki; 28th March 2010 at 08:46 PM. Reason: Second thoughts... |
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#4 | |
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diyAudio Member
Join Date: Nov 2009
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Quote:
The threshold voltage is subtracted from the signal in: If signal in = 2V and threshold = 1V then the output of the opamp is: 2 - 1 = 1V If signal in = 1V and the threshold = 2V, then the output is: 1 - 2 = -1V As you can see, any signal below the threshold will result in a negative voltage. However, in order for the compressor to work these negative voltages must somehow be blocked, or converted to 0V. I hope this clears the question up! Last edited by dan_thompson87; 28th March 2010 at 08:58 PM. |
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#5 | |
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diyAudio Member
Join Date: Nov 2009
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Quote:
Thanks guys! Last edited by dan_thompson87; 28th March 2010 at 09:07 PM. |
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