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#1 |
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diyAudio Member
Join Date: Feb 2008
Location: York, UK
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This is probably a stupid question but googling is getting me nowhere; I'm building a Phono Pre-amp it's going to be battery powered by 8x 9v Batteries at 36v (regulated to 24v). as it's battery powered every milliwatt is precious and the current limiting resitor for the power LED is going to burn over a watt, is there a simple way of driving a regular LED from this relativly high supply voltage without burning-off a load of energy into a resistor?
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#2 |
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diyAudio Member
Join Date: Sep 2004
Location: UK
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There is no magic solution to this except by using a switch mode voltage converter. Even then the efficiency gain will be marginal and the complexity relatively great.
Are you sure you need a high current in the LED? Try it at 100uA - you will be surprised how bright they can be. Incorporate the LED into one of the amplifier's biasing circuits so that its current is not extra to requirements. |
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#3 | |
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diyAudio Member
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Quote:
What's your basic circuit diagram like ?
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AM |
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#4 |
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diyAudio Member
Join Date: Feb 2008
Location: York, UK
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#5 |
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diyAudio Member
Join Date: Sep 2004
Location: UK
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OK.
In that case there is no perfect bias point. You could put it at the top end of the first 24K load, but then would probably need a second decoupling cap. Or simply use a 100K series R across the 24volt rail. ~ 200 uA current lost - I bet it is bright enough! |
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#6 |
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diyAudio Member
Join Date: Feb 2008
Location: York, UK
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Sounds like a plan!
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#7 |
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diyAudio Member
Join Date: Aug 2004
Location: Ratae Coritanorum
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how about in series with the B+, after the battery, this would require the current drawn from the battery to be any thing up to 30mA or so.
this way there is the same overall power dissipated/wasted in the regulator or regulator and led. dissadvantage is there is a led drop to the positive reg so battery will get to its end point sooner. well somthing to think about at least
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regards bob |
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#8 | |
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diyAudio Member
Join Date: Sep 2004
Location: UK
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Quote:
It "loses" a couple of volts, though. But here that would be no problem at all. |
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#9 |
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diyAudio Member
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You may use a LED as a reference voltage source for your voltage regulator you are going to implement.
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If I disappear suddenly, that means I finally created a time machine and pushed wrong button that brought me to Stalin's Russia. In any experiment any result is the result. Even if it is negative. |
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#10 |
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diyAudio Member
Join Date: Nov 2005
Location: PA
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I recently made a battery operated white noise generator. I stuffed a SLI-580UT3F in the collector circuit of the emitter-follower portion of the output stage which is biased at about 100uA. It's plenty bright. Some of the newer high efficiency red diodes glow impressively bright just with the .5mA diode drop test current of a DMM.
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