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#1 |
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diyAudio Member
Join Date: Feb 2001
Location: Mars
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Two diodes in series, 100v PIV each.
What is total PIV across both ? 200V ? I can't remember, loss of long term brain RAM.... |
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#2 |
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diyAudio Moderator Emeritus
Join Date: Jun 2002
Location: U.K.
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Hi,
I believe that PIV is only doubled if you add a leak resistor in parallel with each diode(10K to 10M) depending on the voltage. Personally, I wouldn't push it all the way. Cheers, |
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#3 |
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diyAudio Member
Join Date: Feb 2001
Location: Mars
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The Counsel of Three Head Scratching Elders told me;;;; I always ask the weirdo questions.... |
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#4 |
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Banned
Join Date: Feb 2002
Location: As far from the NOSsers as possible
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A small cap across them would not hurt either, but..........
Why not buy 200 PIV in the first place? The 100 V ones are of a lower grade run than the 200 V ones.....or 400 V ones, etc. Unless you are using Schottky. Jocko |
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#5 |
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diyAudio Member
Join Date: Feb 2001
Location: Mars
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It's more or less just an exam type of question, I'm
not building anything. So far no definitive answer given I'm afraid to ask the second question. scenario; Ordinary NPN transistor with a V(br)EBO = 5V (emitter-base breakdown voltage). Reverse bias of base/emitter > 5V = bad news for the transistor? if yes then second question A ordinary diode in series with base of this transistor reversed biased, the anode connects to base. Diode PIV = 100v. What is total reverse bias breakdown voltage between cathode and emitter ?
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#6 | |
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diyAudio Moderator Emeritus
Join Date: Jun 2002
Location: U.K.
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Quote:
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