Ratio of power into load and driver transistor
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 27th November 2009, 12:58 AM #2 nigelwright7557   diyAudio Member     Join Date: Apr 2008 Location: Carlisle, England For.a.4.ohm.load.and.60.volt.b+ Applied.sine.wave.peak.voltage....power.in.transis tor....power.in.speaker. 60..........................................116... .....................439 50..........................................154... .....................304 40..........................................166... .....................193 30..........................................156... .....................107 20..........................................116... .....................46 10..........................................60.... ......................10 It can be seen that there is more power in the transistor at around a 30 volt sine wave than on 60 volt sine wave. __________________ PCBCAD51 pcb design software. 2018 version out now with lower prices >> http://www.murtonpikesystems.co.uk Last edited by nigelwright7557; 27th November 2009 at 01:01 AM.
 27th November 2009, 12:59 PM #3 Elvee   diyAudio Member     Join Date: Sep 2006 Congratulations: you have just reinvented the wheel (sort of): http://www.phy.auckland.ac.nz/Staff/...amplifiers.pdf
 27th November 2009, 02:07 PM #4 sregor   diyAudio Member   Join Date: Jan 2006 Location: massachusetts Your numbers are in the right ballpark, but seem off. I'm not familiar with the program language, but it looks you should be diding your steps by 360, not 256. RMS voltage should be .6366 times peak voltage, which would give you a power of 357 watts into a 4 ohm load, and 89.25 at 30 volts peak. __________________ Steve
nigelwright7557
diyAudio Member

Join Date: Apr 2008
Location: Carlisle, England
Quote:
 Originally Posted by sregor Your numbers are in the right ballpark, but seem off. I'm not familiar with the program language, but it looks you should be diding your steps by 360, not 256. RMS voltage should be .6366 times peak voltage, which would give you a power of 357 watts into a 4 ohm load, and 89.25 at 30 volts peak.
The divide by 256 is because the sine table values are 0-255 and not 0-1, I pinched the table from anotehr program of mine.

Your absolutely right I should divide by 360 because there are 360 samples taken which is just the same as integrating. I have now added a div 360 on my program and it makes much more sense now.
__________________
PCBCAD51 pcb design software. 2018 version out now with lower prices >> http://www.murtonpikesystems.co.uk

nigelwright7557
diyAudio Member

Join Date: Apr 2008
Location: Carlisle, England
Quote:
 Originally Posted by Elvee Congratulations: you have just reinvented the wheel (sort of): http://www.phy.auckland.ac.nz/Staff/...amplifiers.pdf
Yes it looks pretty much what I came up with just integrating the results over a full cycle.

It was interesting to do because I also added another variable for the amplitude of the sine wave so I could try different amplitude sines with different b+ rails.
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PCBCAD51 pcb design software. 2018 version out now with lower prices >> http://www.murtonpikesystems.co.uk

Elvee
diyAudio Member

Join Date: Sep 2006
Quote:
 Originally Posted by nigelwright7557 Yes it looks pretty much what I came up with just integrating the results over a full cycle. It was interesting to do because I also added another variable for the amplitude of the sine wave so I could try different amplitude sines with different b+ rails.
Formula (16) does that, and shows that max dissipation occurs when the supply to output voltage ratio is pi/2, independent of the absolute voltage level, load, etc

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