Amplifier theoratical max rated output power based on supply voltage
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theAnonymous1
diyAudio Member

Join Date: Feb 2004
Location: Anonymityville
Quote:
 Originally Posted by AndrewT if you can remember that I = V / R - Ohm's law and that P = I * V then all the others follow exactly from those two equations. No reason to be either lazy nor stupid. But frequent repetition may well be required to commit this to permanent memory, for it to stick. Just like a PC:- RAM is volatile and HDD can be almost permanent, if we know where the index to the library/files is kept.
My memory is extremely volatile.

It took a long time to get this image burned into my EEPROM.....

Last edited by theAnonymous1; 26th September 2009 at 11:03 AM.

Nico Ras
diyAudio Member

Join Date: Nov 2005
Location: East Coast of South Africa
Quote:
 The formula is: P[RMS] = Ec^2/(8*Rl) where: P is the RMS power in watts Ec is the supply voltage. In your case, is either 10V or +/-5V=10V (same thing) Rl=Load resistance in ohms. In your case, the RMS power is 10^2/(8 * 10) = 1.25W
There exists no such thing as RMS watt

wwenze
diyAudio Member

Join Date: Mar 2008
Quote:
 Originally Posted by theAnonymous1 My memory is extremely volatile. It took a long time to get this image burned into my EEPROM.....
Strange, I had P = V * I etched into my brain since I was a child. Must be my father showing me the utility bill.

AndrewT
diyAudio Member

Join Date: Jul 2004
Location: Scottish Borders
Quote:
 Originally Posted by wwenze Strange, I had P = V * I etched into my brain since I was a child. Must be my father showing me the utility bill.
yes that's what it says.
P=I*E
I=P/E
E=P/I

where
P=power
I=rms current
E=rms voltage
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regards Andrew T.

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