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18th September 2009, 05:23 PM
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#2 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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50W into 8r0 is the same as 20Vac into 8r0.
100W into 8r0 is the same as 28.28Vac into 8r0. A compression driver is unlikely o be rated for a continuous 50W of input. They are used to seeing a few milliseconds of input at the higher voltage levels and sustained power about 10 to 20dB below the maximum rating. 1kHz and 28.29Vac (=40Vpk) may take your compression driver way past it's Xmax and even past it's Xmech!!!!
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regards Andrew T. |
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18th September 2009, 05:59 PM
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#3 |
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diyAudio Member
Join Date: Apr 2009
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It is to test protection circuit without amplifier connection to compression driver.
I will use 8 ohm resistor as load. The 50W/100W will hv to be passed through -4.5db L pad, -18db crossover & then protection circuit with PTC & resistor+ bulb in parallel. So want to set the amplifier output to check the circuit. Any other suggestion will be appreciated. |
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18th September 2009, 06:51 PM
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#4 |
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Did it Himself
diyAudio Member
Join Date: Nov 2003
Location: Gloucestershire, England, UK
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You don't need 8 ohm resistor load, just set amp to voltages as Andrew has told you.
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www.readresearch.co.uk my website for UK diy audio people - designs, PCBs, kits and more |
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Setting amplifier output power level
