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Old 15th May 2003, 01:40 AM   #1
sam9 is offline sam9  United States
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Default Breeder resistor action

Anyone have an opinion about how long bleeder resistors should take to drain the caps in a power supply? In terms of them being a saftey feature, I've assumed 1-2 minutes is about right since it would take at least that long to open the enclosure. I don't want it be so short that I'm wasting current, either.

I don't think it needs the be fool-proof since I expect to be the only fool opening the amp
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Old 15th May 2003, 01:41 AM   #2
sam9 is offline sam9  United States
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Default I mean bleeder not breeder!!

Yeesh!
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Old 15th May 2003, 01:50 AM   #3
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darn. i thought it was some advancement in biotechnology. self-replicating components, or something.
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Old 15th May 2003, 03:00 AM   #4
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I thought it migh be a resistor of oriential origin.
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Old 15th May 2003, 03:30 AM   #5
karma is offline karma  Canada
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lol for me when i work on em.i use a old 120watt safety light and
discharge it i dont trust any bleeder resister. i likelly will be told it's not the right way to do it but it works


warning high voltages dont find out the hard way like i did trusting a resister !!hoohaaahollymonky
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Old 15th May 2003, 12:41 PM   #6
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This is a typical trade off.

Short time = Heat.

I should think a time between 5-30 seconds is normal. You could also have an active solution with a transistor or relay + resistor.
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Old 15th May 2003, 03:47 PM   #7
sam9 is offline sam9  United States
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Thanks Peranders, more the response I was looking for.

Although it's my own fault I got the other responses, being a clumbsy typist.
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Old 15th May 2003, 04:08 PM   #8
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Be carefull if you are using inductive filter ( choke ) there is a minimum current needed to maintain magnetic flux in core to make shure inductor is making filtering action
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Old 15th May 2003, 08:48 PM   #9
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bleeders are discussed in the ARRL handbook -- and the discharge time should be short, like 90% within a second or so. the formula for discharge is

E(sub t)/E(initial) = e^(-t/RC)
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