
Home  Forums  Rules  Articles  diyAudio Store  Blogs  Gallery  Wiki  Register  Donations  FAQ  Calendar  Search  Today's Posts  Mark Forums Read  Search 
Solid State Talk all about solid state amplification. 

Please consider donating to help us continue to serve you.
Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving 

Thread Tools  Search this Thread 
24th May 2008, 09:43 PM  #1 
diyAudio Member
Join Date: Apr 2008
Location: Carlisle, England

Output transistor power dissipation.
Does anyone know what the function is for power dissipation in an output transistor for a sine wave input ?
1/ The output transistor is only on for half of the sine waveform. 2/ As the output voltage approaches zero and V+ the pwoer dissipation approaches zero. 3/ Max power dissipation seems to be a maximum at half V+/
__________________
MurtonPike Systems PCBCAD51 pcb design software. http://www.murtonpikesystems.co.uk 
25th May 2008, 08:08 AM  #2 
diyAudio Member
Join Date: Dec 2002
Location: Left of the Dial

According to the National Semiconductor Audio/Radio Handbook, max Pd occurs when the peaktopeak output voltage is 0.637 times the power supply voltage. At that level, assuming that all Class B power is dissipated by the output transistors, dissipation is:
max Pd = Vs²/(2pi²Rl) = ~ Vs²/(20Rl) Vs= Supply voltage (absolute value of V+ and V added if using split supplies) Rl=Load impedance The end result of the calculation is the maximum total power dissipated by that amplifier channel. 
25th May 2008, 12:16 PM  #3  
diyAudio Member
Join Date: Apr 2008
Location: Carlisle, England

Quote:
Many thanks. My current method was to keep adding output pairs until they dont run too hot !
__________________
MurtonPike Systems PCBCAD51 pcb design software. http://www.murtonpikesystems.co.uk 

25th May 2008, 04:43 PM  #4 
diyAudio Member
Join Date: Dec 2006

i once saw an AES paper that used 7075% rated output power as the figure for max dissipation (it's probably 70.7% since that's the RMS value of the waveform peaks at half the supply voltages).
__________________
Vintage Audio and ProAudio repair ampz(removethis)@sohonet.net spammer trap: spammers must die 
25th May 2008, 09:38 PM  #5 
diyAudio Member
Join Date: Dec 2002
Location: Left of the Dial

No, maximum disappation is, as I posted above, when the PP output is 0.637 times Vs. No guessing to it.
NS provides the derivation for this figure in the book. I'm too rusty with my calculus to follow, but if anyone insists I can scan the page. 
25th May 2008, 09:44 PM  #6  
diyAudio Member
Join Date: Apr 2008
Location: Carlisle, England

Quote:
It would be interesting to see the page.
__________________
MurtonPike Systems PCBCAD51 pcb design software. http://www.murtonpikesystems.co.uk 

25th May 2008, 09:50 PM  #7 
diyAudio Member
Join Date: Mar 2001
Location: Sydney

You should have a look at this thread, as AndrewT made some very valid points regarding voltage and current phase shift, which for all loudspeaker loads will have a significant impact on device dissipation.
http://www.diyaudio.com/forums/showt...hreadid=106007 
26th May 2008, 12:06 AM  #8 
diyAudio Member
Join Date: Apr 2005
Location: In the Wild, Wild West

The instantaneous device Pd is higher than the maximum Pd predicted by the equation in the handbook, Pd = Vcc^2/(2pi^2Rload). This equation gives the maximum AMPLIFIER power dissipation for a Class AB amplifier. It is the 50% efficiency point if you plot the curve of Pd vs Pout. I have done this many times and the point is accurately predicted. The problem is that this is the average power dissipation for the entire output stage. As noted, one half is doing on side of the sine wave. So the peak instantaneous is actually higher. Then you add in the phase difference between V and I and it goes up more. I don't know what the best number is to use for safe amplifier design. I think you can take into account the time at these higher levels, like FETs have a DC rating as well as a 10ms or some other short time SOA rating. Someday I'll figure it all out mathematically (all it is is math) and nail it down.
SL 
26th May 2008, 01:51 AM  #9  
diyAudio Member
Join Date: Dec 2002
Location: Left of the Dial

Quote:
Quote:
Max Pd = 4Po(Max)/(pi²cosč) (Edit: the symbol for theta doesn't seem to be working...the last part of the denominator is cosine theta). Anyway, here is the proof for the previous formula (good for only a few days and something like 100 downloads, unless someone has a few MB of online space and would like to host it): http://download.yousendit.com/D87BE2D430B33F1A 

26th May 2008, 02:00 AM  #10 
diyAudio Moderator

the number of output transistor pairs in your output is determined by your LOAD...
then your wallet....
__________________
planet10 needs your help: Let's help Ruth and Dave...http://www.diyaudio.com/forums/plane...ml#post5010547[B 
Thread Tools  Search this Thread 


Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
bipolar (bjt) transistor families for audio power output stages  tiefbassuebertr  Solid State  830  5th August 2017 10:39 AM 
Favorite High Power Output Transistor  mashaffer  Solid State  520  21st July 2010 12:52 PM 
power transistor output capacitance  hienrich  Solid State  3  26th December 2004 07:18 AM 
New To Site?  Need Help? 