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Old 24th April 2008, 08:18 PM   #31
jenks is offline jenks  United Kingdom
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In order to do the transfer function did you firstly combine some of the capacitors and potentiometers like so:

C1 and (1-Kb)R2 in parallel and then C2 and KbR2 in parallel as well so that you can effectively separate the capacitors with the potentiometer into two components that lie in series with R1?
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Old 24th April 2008, 08:28 PM   #32
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Quote:
Originally posted by jenks
In order to do the transfer function did you firstly combine some of the capacitors and potentiometers like so:

C1 and (1-Kb)R2 in parallel and then C2 and KbR2 in parallel as well so that you can effectively separate the capacitors with the potentiometer into two components that lie in series with R1?
I think the answer is yes. :-)

I should have shown the potentiometer as two resistors, rather than as one. For the purpose of the analysis it's treated as two, split at the arrow, as you have described.
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