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#1 |
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diyAudio Member
Join Date: Jun 2004
Location: London
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Hi all
I'm thinking of using a joshua tree attenuator but am failing to grasp the concept and application. I have a CD player and it's output is a 2.2uf capacitor followed by a 100K resistor to ground. Will I get bass rool off? Does the current standard JT 'mimmick' a 100K or 50K pot so the signal is 100K or 50K 'away' from gound or what? I'm missing something aren't I R
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#2 |
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diyAudio Member
Join Date: Jul 2004
Location: ALSACE
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Hi Rob
From a resistance point of view, the tree attenuator doesn't act like a pot. A pot has a constant input resistance and varying output resistance. A JT has a varying input resistance and constant output resistance. JT's minimum input resistance=1.8K (-63.5dB) and max=30.5K (-32dB) with the standard values offered by Pear's Audio. It's way too low for you and the corner frequency will be 40Hz. Higher resistor values can be used, but then you will have an issue at your amp's input. A solution would be to add a buffer between the source and the JT, but it must have low dc offset to minimize switching noise. I bought one kit recently, it's nicely done, but I still found no time to build it. Cheers, Francis |
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#3 |
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diyAudio Member
Join Date: Jul 2004
Location: ALSACE
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Attached txt file with Rin and Rout for each setting.
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#4 |
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diyAudio Member
Join Date: Jun 2004
Location: London
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Thanks for that.
I had a feeling that was the case. R |
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