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Old 22nd February 2008, 06:05 PM   #1
kmj is offline kmj  Sweden
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Default To debounce a soft switch

Hi, I got this soft switch from a friend and since I needed three for my system I put them together. The problem is that they bounce something terrible. My undeducated guess is that the NE555 sences the pulse from the switch and then "tells" the transistor to activate the relay. The bouncing is due to the fact that the little chip reacts to every litte disturbance it comes across and the solution is to make the NE555 ignore shorter pulses and just react to some more firm ones.

So, am I right and if so, how do I do it?

The circuit I used is attached and I hope that it is OK to post it. Since I don't know where it came from I can't ask.
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File Type: gif onoff3_369m.gif (12.2 KB, 171 views)
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Old 22nd February 2008, 07:55 PM   #2
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Default Hi kmj!

Try this, work 1000%.

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Old 22nd February 2008, 08:02 PM   #3
kmj is offline kmj  Sweden
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that looks easy enough.

I can use the transistors I have at hand I suppose?

The cd4014, that is a dual flip-flop, right?
This one
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Old 22nd February 2008, 08:13 PM   #4
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Default Hi kmj!

CD4014 is 8-bit static shift register.

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Old 22nd February 2008, 08:38 PM   #5
gootee is offline gootee  United States
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Default Re: Hi kmj!

Quote:
Originally posted by zeonrider
CD4014 is 8-bit static shift register.

Regards zeoN_Rider
I guess he meant to ask about the CD4013 that is in your schematic.
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Old 22nd February 2008, 08:40 PM   #6
kmj is offline kmj  Sweden
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oh, thats right. My mistake
4013 it is
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Old 22nd February 2008, 08:42 PM   #7
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Default Hi!

I, don't know what he meant.

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Old 22nd February 2008, 08:54 PM   #8
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That is better!

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Old 22nd February 2008, 09:02 PM   #9
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Check out this simple latch circuit. It will insure a perfectly debounced state on the output at all times. Any metastate due to switch bounce will leave the output in its last state. Follow the logic and you will see.
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