
Home  Forums  Rules  Articles  diyAudio Store  Gallery  Wiki  Blogs  Register  Donations  FAQ  Calendar  Search  Today's Posts  Mark Forums Read  Search 
Solid State Talk all about solid state amplification. 

Please consider donating to help us continue to serve you.
Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving 

Thread Tools  Search this Thread 
8th February 2008, 11:30 AM  #1 
diyAudio Member
Join Date: Jan 2008

Gain calculations
Hi
I'm just working through Douglas Selfs book and running through some of the calculations. At the moment I'm looking at LF and HF gain He gives LF gain to be gm*Beta*Rc Could someone just clarify that the following assumptions are correct please? gm in mA/V? Beta is that of VAs transistor? and if a darlington stage is used, does that need to be used as beta*beta in the equation? Rc is the output resistance of the VAS current source? I know it's going to be quite high, but can someone tell me how to calculate it for a common 2 transistor CC? I know I should be able to work this one out, but I think I've been looking at textbooks for too long and I can't see the wood for the trees now! At the moment I'm getting a horrifyingly large number for a circuit setup with gm=95mA/V beta=14400 for 2 2SD669s in VAS, and 5Mohm for the VAS current source. I've done a lot of searching, but failed to find anything that can help yet. Thanks for looking Ian 
8th February 2008, 11:39 AM  #2 
diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders

2sd669 are good for drivers not for VAS and predrivers.
Use 2sa1360/c3423 or similar for their low capacitance. If VAS power is low then To92 devices can be used.
__________________
regards Andrew T. Sent from my desktop computer using a keyboard 
8th February 2008, 11:50 AM  #3 
diyAudio Member
Join Date: Jan 2008

Thanks for the suggestion
I went with the 669s because Randy Slone uses them in almost all his designs, and they were recommended in a few threads on here. Self tends to use MJE340s quite a lot, but they really are slow! I do see what you mean about the cob for the 3423  5 times less than the 669! 
13th February 2008, 06:57 PM  #4 
diyAudio Member
Join Date: Feb 2008

Hello,
Are there any other suitable Bjts for VAS other than 2sa/2sc? 
13th February 2008, 10:47 PM  #5 
diyAudio Member
Join Date: Jan 2008

Look for something with a good ft, and low collector capacitance. Can noone here help me out with the calculations? Or at least point me in the right direction.

13th February 2008, 11:01 PM  #6 
diyAudio Member
Join Date: Feb 2008

hello
Yes gm is in ma/V I think it is the gain of a LTP where Rc is the collector load(hope i'm not wrong with this). Yes if you have a darl'ton you must multiply the two betas 
13th February 2008, 11:17 PM  #7 
diyAudio Member
Join Date: Jan 2008

Brilliant, thanks for that. Very much appreciated
So we have (gain of LPT in mA/V)*(current gain of VAS)*(resistance of VAS collector load) Which does make sense, and the first two I can calculate. The last piece of the puzzle here is how to work out or measure the effective resistance of the current source. Any takers on this one? 
14th February 2008, 03:51 PM  #8 
diyAudio Member
Join Date: Nov 2005

For measuring the effective resistance of the current source, say you have a 15V supply. Put a low resistance in line with the current source so there is a voltage drop of 14V across the current source. No measure the current flowing into the collector of the current source. Lets say it is 1mA. Now put a larger resistor inline with the current source so the voltage across the current source is 1V. Now measure the current flowing into the current source. Lets say it measures to 0.991mA. Now do this formula: (14V1V)/(1mA0.991mA) which calculates to 1.44Mohms.
So it is basically change in voltage across current source/change in current flowing through current source which is R=V/I. The voltage change across the current source is created by changing the resistance inline with the current source which inturn changes the voltage across the current source. The current is measured at each different voltage level. The effective resistance would always be changing but would stay high. In the example above, it should always be at least 1.44Mohms or higher in resistance as long as you are staying with in the limitations of the current source. This is a dynamic measurement. A static measurement would be voltage across current source/current flowing in current source which would be 14kohms for the first measurement, unless I am wrong. 
14th February 2008, 04:31 PM  #9 
diyAudio Member
Join Date: Jan 2008

That's exaclty what I'm looking for, thank you very much
I'll get on with finding the output impedance of my CCS. Thanks to everyone for their assistance 
14th February 2008, 04:35 PM  #10  
diyAudio Member
Join Date: Aug 2005
Location: Ktown

Quote:
What Vce do you need? This is an important variable to consider when choosing VAS transistor(s).
__________________
All the trouble I've ever been in started out as fun...... 

Thread Tools  Search this Thread 


Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Heretical Unity Gain line stage PLUS a little gain ?  yagas  Tubes / Valves  7  24th January 2006 02:30 PM 
gain calculations  demons_wing  Solid State  5  12th May 2004 12:33 AM 
Current Gain Calculations  JDeV  Pass Labs  3  28th January 2003 12:47 AM 
New To Site?  Need Help? 