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#11 | |
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diyAudio Member
Join Date: Aug 2005
Location: K-town
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Quote:
Yes. When the signal is peak, there would be 5A through 1 Ohm, and that makes 5V. The goal is to have rail to rail voltage swing because the less voltage left in the circuit, the less power in heat it has to dissapate. There may be a couple of volts on the transistor too so that is like 7 potential volts missing from the output. These resistors are degeneration resistors. R7 & R13 are a form of negative feedback for the output transistors. If they are too large, you lose voltage gain in the follower at the output node. They also limit current for protection since BJT's can have a very high conductance so there is still need for them.
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All the trouble I've ever been in started out as fun...... |
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#12 |
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diyAudio Member
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Q15/Q16 to be matched and in thermal contact with each other.
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#13 | |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Quote:
if the two sides of the input long tail pair (LTP) are to be balanced for least output offset and least output offset drift then DC blocking caps must be fitted to both the input from the source and also to the lower leg of the NFB loop. Or no DC blocking caps to either side of the LTP. NOT mixed DC blocking/AC coupling. The driver emitter resistor determines the driver bias (quiescent) current. If this is set very low the driver turns off very early in the amplification process. I don't have data/research to back up this next assertion but I think the driver should stay in ClassA longer than the output devices before each stage starts to go into ClassAB as output currents rise. Q11 develops a low voltage across it when it triggers. This allows very large currents to flow without risk of damage to Q11. But Q13 starts to develop a very large voltage across it and also increasing current flows. The power dissipated in the junction can be considerable for the brief period that the protection transistor conducts. The string R3, Q13, D1, Q11 connects Vrail to output and a short or failed output device connects to either ground or the opposite Vrail. Calculate the Vdrops across each device and estimate the fault current that will flow. You can now estimate the dissipation across each device and see which are most at risk of damage, not necessarily destruction.
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regards Andrew T. |
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