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Old 3rd February 2003, 08:07 AM   #1
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Location: Denmark
Default BJT - how can the output device manage

Hi everybody, I'm trying to understand.

Having buildt several version og P3A, sounding great i'm thinking of a BJT version as it is the way most of you suggest for more power. But can the outputdevice handle twice the current ?

Say at 32W the current is 2A - the voltage is 16v RMS, rigth ?
If you BJT 2 modules the voltage is 32v RMS, the current 4A, and 128W. 8Ohm example.

4A will then run trough both modules rigth ?, and you have to calculate with this designing your output-stage right ?

Any comments are wellcome, - thanks.
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Old 3rd February 2003, 11:16 AM   #2
e96mlo is offline e96mlo  Sweden
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Join Date: Apr 2002
Location: Helsingborg, Sweden
BJT = Bipolar Junction Transistor
BTL = Bridge Tied Load

Don't you mean BTL?

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Old 3rd February 2003, 11:19 AM   #3
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Stupid me !

I mean BTL - bridged mode,
Thank You Marcus
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Old 3rd February 2003, 11:25 AM   #4
OliverD is offline OliverD  Germany
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In BTL, every amp of the bridge "sees" half of the speaker impedance at its output. If you have an 8 ohm speaker and both channels of the bridge can handle 4 ohm speakers, it will work without modifying the output stages.
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