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(LT)spice model for 6J7
(LT)spice model for 6J7
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Old 15th December 2012, 01:33 PM   #1
JoeAlders is offline JoeAlders  Netherlands
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Join Date: Feb 2011
Default (LT)spice model for 6J7

Is there somebody who can supply me with a (LT)spice model of the pentode 6J7,
or where can I find a description on the internet? Browsing on the net myself did not give me any clue (for instance Duncan's pages or others).
Or, is it possible to modify an existing pentode model to get a workable model?
Thanks in advance,
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Old 19th December 2012, 07:34 AM   #2
cogsncogs is online now cogsncogs  United States
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Join Date: Jul 2003
Location: Wayne, West Virginia
To use this model in LTSpice change all instances of ^ to **.
* Generic pentode model: 6J7
* Copyright 2003--2006 by Ayumi Nakabayashi, All rights reserved.
* Version 3.01, Generated on Wed Mar 22 17:20:43 2006
BGG   GG   0 V=V(G1,K)+0.75953915
BEP   EP   0 V=URAMP(V(A,K))+1e-10
BEG   EG   0 V=URAMP(V(G1,K))+1e-10
BEG2  EG2  0 V=URAMP(V(G2,K))+1e-10
BM1   M1   0 V=(0.0057490544*(URAMP(V(EG2)-1e-10)+1e-10))^-0.20145614
BM2   M2   0 V=(0.88159781*(URAMP(V(GG)+V(EG2)/20.595073)+1e-10))^1.7014561
BP    P    0 V=0.00080605414*(URAMP(V(GG)+V(EG2)/23.361076)+1e-10)^1.5
BIK   IK   0 V=U(V(GG))*V(P)+(1-U(V(GG)))*0.00053791349*V(M1)*V(M2)
BIG   IG   0 V=0.00040302707*V(EG)^1.5*(V(EG)/(V(EP)+V(EG))*1.2+0.4)
BIK2  IK2  0 V=V(IK,IG)*(1-0.4*(EXP(-V(EP)/V(EG2)*15)-EXP(-15)))
BIG2T IG2T 0 V=V(IK2)*(0.82254609*(1-V(EP)/(V(EP)+10))^1.5+0.17745391)
BIK3  IK3  0 V=V(IK2)*(V(EP)+7400)/(V(EG2)+7400)
BIK4  IK4  0 V=V(IK3)-URAMP(V(IK3)-(0.00045533328*(V(EP)+URAMP(V(EG2,EP)))^1.5))
BIP   IP   0 V=URAMP(V(IK4,IG2T)-URAMP(V(IK4,IG2T)-(0.00045533328*V(EP)^1.5)))
BIAK  A    K I=V(IP)+1e-10*V(A,K)
BIGK  G1   K I=V(IG)
CGA   G1  A  0.005p
CGK   G1  K  4.2p
C12   G1  G2 2.8p
CAK   A   K  12p
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Old 19th December 2012, 07:51 AM   #3
JoeAlders is offline JoeAlders  Netherlands
diyAudio Member
Join Date: Feb 2011
Thank you very much cogsncogs!

At first I was afraid that nobody could help me in this matter
due to a lack of response.
Thanks again!
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