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#1 |
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diyAudio Member
Join Date: Oct 2008
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Hi,
I'm trying to simulate a mic preamp with an EF86. The problem is that all spice model avaible on the net have only 4 connections like in this one *Vacuum Tube Tetrode EF86 .SUBCKT XEF86 A S G K * * Calculate reduction in mu when Vg < -3V * Bmu mu 0 V=V(G,K)+URAMP(V(K,G)-3)*0.4 * * Calculate contribution to cathode current * Bat at 0 V=0.636*ATAN(V(A,K)/15) Bgs gs 0 V=URAMP(V(S,K)/27.5+V(mu)*1.32+1) Bgs2 gs2 0 V=URAMP(V(gs))^1.5 Bcath cc 0 V=V(gs2)*V(at) * * Calculate anode current * Ba A K I=5.83E-4*V(cc) * * Calculate screen current * ** S K I=0.5E-3*V(gs2)*(1.1-V(at)) * * Capacitances * Cg1 G K 3.8p Cak A K 5.3p Cg1a G A 0.05p .ENDS XEF86 But the EF86 is a pentode!! Can somebody please explain me why all model are tetrode and if there is somewhere a pentode model for this tube? |
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#2 |
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diyAudio Member
Join Date: Dec 2006
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because 99.99% of the time, the suppressor is connected directly to the cathode, and the tube is modeled as a tetrode with pentode characteristics. the only exception would be if you were using the suppressor as a gain control element, and that isn't done very often. a pentagrid converter was usually used for that. more often, the screen grid is used as the multiplier input on a pentode.
Last edited by unclejed613; 20th February 2010 at 06:26 PM. |
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#3 |
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diyAudio Member
Join Date: Oct 2008
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thanks for reply.
I wanted to build a mic preamp and the suppressor grid is connected to ground and I want to know how much gain it produce. |
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#4 |
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diyAudio Member
Join Date: Dec 2006
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is the cathode also grounded?
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#5 |
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diyAudio Member
Join Date: Oct 2008
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no trough resistor and bypass cap
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