This is absolute a cool gadget for audio DIYers. It convert 12V from car battery to dual ±45V DC power supply for audio amplifiers. Voltage is adjustable by adding feedback resistors in parallel with the on board res. The max power is up to 500W! Don't tell me it's not enough for your car audio...
See details here:
500W 12V to ±45V car audio PSU
See details here:
500W 12V to ±45V car audio PSU
An externally hosted image should be here but it was not working when we last tested it.
An externally hosted image should be here but it was not working when we last tested it.
Last edited:
Did a test today with a electronic load. The voltage was set to 45V, current set to 6A. Postive and negative output are tested seperated because the electronic load don't have dual input 🙂
Positive voltage dropped from 45.1V to 44.7V and negative voltage drops from -45.1V to -44.8V. Result is quite positive.
Positive voltage dropped from 45.1V to 44.7V and negative voltage drops from -45.1V to -44.8V. Result is quite positive.
More pics. The newest version upgrated the MOSFET with a more powerful part. Output is more stable.
An externally hosted image should be here but it was not working when we last tested it.
An externally hosted image should be here but it was not working when we last tested it.
An externally hosted image should be here but it was not working when we last tested it.
I have a quick question. If I were to use this at +/- 18V, could it handle the continuous power draw of 2 F5 amplifier boards?
The F 5 needs about 1.3A, with +/-24Vdc (not sure why I used 18V). That is continuous current, though.
the F5 will draw up to 2.6A pr ch.
1.3A at idle and up to the point it switch to class B.
but yes. it can be used on 2ch of F5.
1.3A at idle and up to the point it switch to class B.
but yes. it can be used on 2ch of F5.
I had a quick question regarding this module. How do you set the output voltage to be less? I know that you just have to put a resistor in parallel but say I wanted +/- 25V what value would I put in parallel?
I would also like to know this. Is it possible to soldier in a pot here? If so what would you recommend?
What I've found is that... you can determine your new output voltage by using the following equation...
45V / 82.6kohms = new voltage / new equivalent resistance.
45V / 82.6kohms = new voltage / new equivalent resistance.
Hello s sorry for the late reply.
Please look at the schematic below:
the feedback network is formed by R24//R20 + R11 and R21//R25 + R22. Voltage on Pin14 is 5.0V. The voltage on Pin15 must equal to pin 16. R20 and R21 is actually 82.6ko. It's not quite complicate to calcualte the value of R24 and R25 with this conditions.
Please look at the schematic below:
An externally hosted image should be here but it was not working when we last tested it.
the feedback network is formed by R24//R20 + R11 and R21//R25 + R22. Voltage on Pin14 is 5.0V. The voltage on Pin15 must equal to pin 16. R20 and R21 is actually 82.6ko. It's not quite complicate to calcualte the value of R24 and R25 with this conditions.
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