| 0,0047uF = 47pF? - Click HERE for Original Thread |
| Bas Horneman |
Sorry for asking such a trivial question...but
is 0,0047uF equal to 47pF??? |
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| jean-paul |
No, it's 4.7 nF. Which is the same as 4700 pF.
On your calculator:
uF is 10 with exponent -6.
nF is 10 with exponent -9
and pF is 10 with exponent -12.
Note that the international way to express these values is by using a dot instead of a comma. In Europe we write down 4,7 which confuses others. We write down 10.000 for ten thousand whilst the Americans write down 10,000 for the same thing.( If I'm correct ). |
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| Austin |
.0047uF would be 4.7nF and 4700pF
uF=10^-6
nF=10^-9
pF=10^-12
Austin |
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| Bas Horneman |
47pf would thus be 0,0000047uF?
Thanks for the replies! |
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| UrSv |
| quote: | Originally posted by Bas Horneman
47pf would thus be 0,0000047uF?
Thanks for the replies! |
No, it would be 0,000047uF.
/UrSv |
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| jean-paul |
Bas, if you use the 0,0000xxx way of noting values errors creep in easily.
Try the exponent way of expressing these values on your calculator and your cross over filters will require much smaller caps ( or bigger ) than you calculated before ;) |
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| chris ma |
Hi,
Please check the numbers here;) |
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| sam9 |
| Who decided on making a Farad so big, anyway? Ocassionally, ones sees a 1F cap used for an autosound system (the one that drives you nuts sitting at a stop light, no doubt). Otherwise, it seems of no use except to microwave a cow or fire up 'ole sparky. |
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| chris ma |
Ah...Far..rad....I remember there used to be a guy around called Faraday, might have been a DIYer too....
Chris :) |
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| janneman |
| quote: | Originally posted by sam9
Who decided on making a Farad so big, anyway? Ocassionally, ones sees a 1F cap used for an autosound system (the one that drives you nuts sitting at a stop light, no doubt). Otherwise, it seems of no use except to microwave a cow or fire up 'ole sparky. |
I think they defined it as a cap that gets charged 1 volt by 1 Amp for 1 Sec. They really couldn't predict we would be working with uamps 100 years later, could they?:cool: ;) :angel:
Jan Didden |
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| JBL |
Mainly to go with other formula without the use of some hard to remember constant and fit well with existing formula.
C=q/V Would not have been that if the Farad would have been smaller.(also the time constant of a RC circuit etc...) |
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| Circlotron |
| quote: | Originally posted by jean-paul
In Europe we write down 4,7 which confuses others. |
Another common way is to write 4n7. Or 4u7, or 4p7. Easy-peasy. |
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| jean-paul |
| quote: | | Another common way is to write 4n7. Or 4u7, or 4p7. Easy-peasy. |
Can't beat that one, Circlotron ! BTW ever seen the 4.7 uuF way of writing ? Saw it once in a tube amp schematic. |
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| dhaen |
| quote: | | BTW ever seen the 4.7 uuF way of writing ? Saw it once in a tube amp schematic. |
Yes, I remember seeing it back in the 60's, but can't remember the age of the schematics.
A thing that catches many people out is the letter tolerance scheme where a resistor marked:
4.7(ohm)K is 4.7 ohms 10%, NOT 4700 ohms:xeye:
Now, why can't I paste a unicode omega symbol in here?
Instead I get §Ù |
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| Thomas |
| quote: | Originally posted by chris ma
Ah...Far..rad....I remember there used to be a guy around called Faraday, might have been a DIYer too....
Chris :) |
If I recall corectly, 1 Farad(ay) is the stored energy of 1 Ampere for 1 Second. |
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| sianturi |
If you keep forgetting how to convert the Farad value, try remembering this:
u:
'micro' -> similar to 'million', but micro multiples the number by 10^-6, whereas 'million' multiplies the number by 10^6
n:
'nano' -> the pronounciation is like 'nine', so it means multiply the number by 10^-9.
p
'pico' -> the smallest multiplication factor between the above. Just remember: between u -> n -> p steps, you must multiply by a factor of 10^3. So:
10^-6 uF = 10^-9 pF = 10^-12 pF.
Thanks to my old high school physics teacher.
Cheers, |
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| sianturi |
| quote: | Originally posted by sianturi
p
...
must multiply by a factor of 10^3. So:
10^-6 uF = 10^-9 pF = 10^-12 pF.
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Oops, got some typos. Here's the correction:
... must multiply by a factor of 10^-3.
Typos corrected. ;) |
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