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X-HDAM Opamp from newbee - Click HERE for Original Thread
aparatusonitus
First of all, I have to say I am a complete beginner in electronic design, so please don't laugh on this one. For this circuit I referenced numerios circuit from Nelson, Ken Ishiwata, Borbely, Kaneda, Elektor, etc. etc... and of course you guys. Is it something completely wrong, is it X, how to fix it, and proceed
with biasing?

http://img.photobucket.com/albums/v...X-HDAMOpamp.png
Nelson Pass
If you want it to be X, I think you need to feed the output
back to the inputs. Feed back ..... :)
aparatusonitus
Hi Nelson,

It's late here, so below is a quick drawing of feedback network. How to prevent "hall of mirrors" efect, e.g. where to connect "magic resistor" and two others?

Good night and thanks Nelson

http://img.photobucket.com/albums/v...AMOpampRev1.png
aparatusonitus
Well, I think this one is more in accordance with Nelson's patent...

http://img.photobucket.com/albums/v...-HDAMOpamp1.png
aparatusonitus
And here is a circuit from moamps (my fellow croatian) , transformed to X-HDAM Opamp Light... I guess

http://img.photobucket.com/albums/v...MOpampLight.png
aparatusonitus
Quote: "An amplifier comprising a first and a second amplifier element, whose outputs are connected to a load, a difference circuit which comprises a comparator, in which the output signal of the first amplifier element is comparated with the input signal thereof to produce a correction signal which is applied to second amplifier element, and a second substantialy identical difference circuit which comprises a comparator in which the output signal of the second amplifier element is compared with the input signal thereof to produce a correction signal which is applied to the first amplifier element; a desired signal to be amplified being applied to both amplifier elements. The two amplifier elements, which may be preceded by a preamplifiers, take the form of power amplifiers. Because the distortion signals appear at the load as "common mode" signals, the overall distortion becomes substabtially zero in the case of equal attentuation in the two difference circuits. The power amplifiers may be provided with a voltage output as well as a current output."

Maybe, but what about noise?
aparatusonitus
...should be like this?

http://img.photobucket.com/albums/v...SyAmplifier.png

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