| Badge |
| I have a couple of Triad power transformers. I would like to design a simple solid state rectifier and LC type power supply. The transformer has two 125 volt secondary outputs with a center tap rated at 22 ma. Each transformer will be driving a 6AR8 tube at 250 volts. Idle demand for this tube is 10 ma. Could someone with suggest a circuit?:confused: |
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| analog_sa |
| Just get PSUDII |
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| Badge |
| Thanks I just downloaded it. My transformers are old stock. I don't have anymore data on them. How do you measure their resistance? |
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| ShiFtY |
So each transformer has two identical 125V secondaries? You could run them in series with the junction as a center tap. Or do you mean they have one secondary with a center tap?
To measure the resistance just break out the multimeter and plug the number into the program.
You have quite a few options, you could use full wave solid state or tube (classic circuit), a diode bridge (gives you higher output voltage), or a hybrid tube-diode bridge. |
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| Badge |
| ShiFtY, the tranny has three wires on the 250 volt side. Two measure 125 volts using the center wire as a ground for measuring. On detemining the resistance, do you measure across the two secondary side taps, or from primary side to secondary? Thanks. |
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| G |
| quote: | Originally posted by Badge
ShiFtY, the tranny has three wires on the 250 volt side. Two measure 125 volts using the center wire as a ground for measuring. On detemining the resistance, do you measure across the two secondary side taps, or from primary side to secondary? Thanks. |
You will need to use a full wave bridge to get the 250 volts you are looking for. Since you are using a bridge the center tap will not enter into the equation. Measure the resistance across the entire secondary and ignore the center tap. You will then need to enter the expected voltage at the secondary (250v) and the dc resistance of the secondary into the program. After that you are ready to simulate. You said the needed current was 10mA per tube? I would assume two tubes so your load will be: 250v/.020 =12.5K. I hope that helps. |
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