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Another PSU question - Click HERE for Original Thread
seventenths
While in the process of building a suitable enclosure for my first gainclone, I started picking up parts for number 2... this may get ugly :)
Anyway, I bought a 48VCT(24+24)/ 500VA tranny, carried it home and powered it up. I put a rectifier across one secondary and the center tap(potted type) and grabbed my meter expecting to see approx- 33-34 VDC . Instead I get a reading of 23V. I then did a quick search of this forum and saw in a post that I should load the output with a resistor (10K suggested). I did this... still 23V.
Am I missing something?


7/10
BWRX
Is your meter set to DC voltage? Since you have a center tapped transformer you want to measure the voltage between the center tap (ground) and each rail after the rectifier.
seventenths
Thank you for the reply...
Yes, my meter is set to DC. ;)
Currently with a 10K resistor across the rectifier +/- connections I get a 23VDC reading (at +/- of rectifier). Set to AC and measuring either sec to center tap, I get 26.4 VAC.... 53.4 VAC from Sec to Sec.
I keep reading that your DC voltage should be 1.41 (?) times the rated VAC, but both of my PSU setups measure a DC voltage roughly equiv to the rated AC output of the XFMR.
My wavetek and my fluke concur...mostly


Thanks
7/10

EDIT* to add; I grabbed my el-cheapo analog meter and it too agrees... 23VDC
jaybombalous
so whats the voltage of just the secondaries on the tran.? Maybe u are getting 1.41 times as much voltage, you just haven't realized it yet. Maybe then again not and your problem lies else where.
FastEddy
Try your rectifier across the full secondary ... your primary may be 220 VAC input and the secondary output is relative to that ... :confused:
sherelec
seventenths,

You are getting the correct answer for your test setup. I am assuming your rectifier is a bridge so the waveform is a fullwave rectified sinewave.

The peak voltage is Vrms*1.414-2*Vd = 26.4V*1.414-1.2V = 36.1V
The Meter on DC will measure the average DC voltage.
Vavg = Vpk*2/Pi = 36.5*2/3.1416 = 23.0V

Close enough?

If you want to see what you were looking for you need to add a filter capacitor across the bridge output.

I hope this is helpful.
VSR

PS: my original post only assumed one diode. By using two at Vd=0.6V the answer comes out to almost exactly 23.0V
hughmon
Do you have some filter caps in place?? If not the DC range on the meter will read funny (as it tries to average the pulsating DC out of the diodes).
FastEddy
sherelec / hugemon: right, right, right ... you have to add some capacitance to the rectifiers to get the peak (stored) DC voltage reading ... :eek:
seventenths
I hope this is helpful.

Only a whole bunch ;) That is exactly what I needed. Thank you all for taking the time to respond. Onward... oh whats that smell... could it be the sizzling 35V cap? Oh yeah some DA got in a rush and didn't reconfigure to the center tap after testing sec-sec


7/10
BWRX
quote:
Originally posted by hughmon
Do you have some filter caps in place?

I just assumed seventenths was using filter caps after rectifiers since this is a power supply thread :cannotbe: It's always the details!
seventenths
BWRX,
I guess I could have expressed my situation more clearly... This isn't a power supply as much as it is a PSU in development. Must of been the excitement... I walked out of the metal shop with WAY more aluminum than I planned on, only to walk into a great deal on a monster tranny at my next stop AND 4 - LM4780's should arrive tomorrow.

Thanks

7/10

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