Vent dimensions when 3 of 4 sides are the enclosure's wall

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I have read in past somewhere that if an enclosure's vent is part of the walls of the enclosure then the length should be counted as having the extra half of the vent's height.For example if a vent has dimensions 40(L)x10(W)x20(D) then the total depth should count as D+1/2(W) or 20+1/2(10)=20+5=25.In simple words it it should be counted as longer than it measures.

Do you agree with this?It sounds like a rule of thumb but seems to have some validity since the 3 walls are extended into the enclosure and only one side,the single wood part is of specific length.
 
with a 1:4 slot ratio, I have typically seen about a ~40% reduction in required port length for a given cross sectional area. Conversely, only ~60% of what theory predicts for length needs to be used in such a situation.

I have here a 1.75 ft³ box (after all displacements) that with a 3"x12" slot port (using 3 enclosure walls) that is 32in long. See if you can find out what frequency it should be tuned to, and then I'll surprise you with what it's actually tuned to. :)
 
FYI:

b:)
 

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with a 1:4 slot ratio, I have typically seen about a ~40% reduction in required port length for a given cross sectional area. Conversely, only ~60% of what theory predicts for length needs to be used in such a situation.

I have here a 1.75 ft³ box (after all displacements) that with a 3"x12" slot port (using 3 enclosure walls) that is 32in long. See if you can find out what frequency it should be tuned to, and then I'll surprise you with what it's actually tuned to. :)

Hi OscarS how do you measure correctly the tuning frequency of the enclosure?I can measure the tuning watching the excursion of the woofer or touching the woofer and feeling the excursion and when the excursion is at the minimum point i consider this as the tuning.But this is not possible with tunings over 40 or 45 Hz where the movement is very fast and the excursion much lower.I have found this way very accurate thought for tunings under 40 Hz.I am very close to what i have simulated before.

Also how true is this 60% number?Have you measured lots of similar enclosures?Have you also measured normal vent enclosures?What were the results for them?

Can you explain the slot 4:1 ratio?
 
This is how I measure tuning:

Dayton Audio DATS Dayton Audio Test System 390-806

As to the 60%, I'm basing it on emperical evidence on enclosures I have built, including the one I mentioned.

by 4:1, I'm talking about the opening of the port. AKA height x width. I mentioned it because it is typically the way I set up my slot ports. I suspect that the reduction in port length will be different for different ratios, aka: "skinnier" ports or more "squareish" ports.

The "K" is called the end correction. It has a certain place in the equation for port length. It modifies the final length calculation to account for different scenarios. You can easily google this equation.
 
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Now i see the ratio meaning :)

My vent is 37,6cm x 9,2cm so the 1:4 is very close!

I have the WT3 software and the hardware too of course.Can i use this to measure the Fb?

This DATS tool seems very similar to my WT3.Maybe it is a replacement for it?Is the WT3 still sold in Parts Express?

Thanks!
 
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Yup, the DATS is the WT3 with slightly different hardware and much improved software. Essentially the same thing for the purposes of this discussion.

If you use a software like WinISD to compute your tuning frequency, you'll see that there will be a huge discrepancy between what it says is required for port length and what you actually have for your particular Fb. Just run an impedance sweep and look at the local minimum in between the two impedance peaks.
 
Then why does that correction factor not correlate with my measured findings? Unless we are applying that correction to different port-length equations.......

Granted my slot port has a bend, but I believe it to be of large enough area to be of little significance.
 
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