Based on the schematic. looks like 3 pairs of outputs. If it runs 100watts class-A into 8 ohms, i'd say the bias is as follows:
Total bias 2.5 amp per rail.
Bias per device 0.84 (x3 devices for each cycle of push pull) .
voltage across each emmitter resistor = 416.6mv.
This amp will dissipate 235 watts per channel at idle.
All this is based on the 100 watt class-A spec and the values on the schematic.
Chocoholic and Millwood, did I make you proud?
K-Amps
Total bias 2.5 amp per rail.
Bias per device 0.84 (x3 devices for each cycle of push pull) .
voltage across each emmitter resistor = 416.6mv.
This amp will dissipate 235 watts per channel at idle.
All this is based on the 100 watt class-A spec and the values on the schematic.
Chocoholic and Millwood, did I make you proud?
K-Amps
Re: The unbiased vue...
I think it is to reduce degeneration for a/c signals without causing excessive d/c offset. with the cap, the two 200r resistors are essentially tied together, thus no more emitter degeneration.
for a/c signal, the cap is open, thus each leg has a 200r resistor.
Tube_Dude said:The unbiased electolitc capacitor in the emmiters of the LTP...is a strange feature...
Any comments??
I think it is to reduce degeneration for a/c signals without causing excessive d/c offset. with the cap, the two 200r resistors are essentially tied together, thus no more emitter degeneration.
for a/c signal, the cap is open, thus each leg has a 200r resistor.
K-amps said:Based on the schematic. looks like 3 pairs of outputs. If it runs 100watts class-A into 8 ohms, i'd say the bias is as follows:
Total bias 2.5 amp per rail.
Bias per device 0.84 (x3 devices for each cycle of push pull) .
voltage across each emmitter resistor = 416.6mv.
This amp will dissipate 235 watts per channel at idle.
All this is based on the 100 watt class-A spec and the values on the schematic.
Chocoholic and Millwood, did I make you proud?
K-Amps
With regards to the 3 pairs of outputs I think it could easily be 4 pairs as the schematic clearly says x4 for the output transistors.
Tube_Dude said:
Not needed the service manual...if the simulation gives you 1mA...your simulation is flawed...
The current un the VAS is +-8,3 mA...
I thought it was settled on that other thread that for such a topology, you cannot calculate VAS and LTP current. Assuming that the current in the LTP legs is evenly split is falwed.
hopefully, the time and effort there were not wasted.
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