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Old 21st February 2007, 06:44 PM   #1
beerman is offline beerman  United States
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Default How to determine ripple voltage?

From http://sound.westhost.com/power-supplies.htm

Quote:
The required capacitance for a given load current and ripple voltage is determined (approximately) by the formula [1]...

C = ( I L / ΔV) * k * 1,000 uF ... where

I L = Load current
ΔV = peak-peak ripple voltage
k = 6 for 120Hz or 7 for 100Hz ripple frequency
Load current is covered, though I can't find anything on peak-peak ripple voltage. What number plugs in here?
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Old 21st February 2007, 06:47 PM   #2
owdi is offline owdi  United States
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plug in however much ripple you are willing to accept. Note the less ripple you specify, the larger the cap.

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Old 21st February 2007, 06:55 PM   #3
beerman is offline beerman  United States
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The next question: how much ripple is acceptable? Should I go off X percentage of +/- DC volts?
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Old 21st February 2007, 07:15 PM   #4
owdi is offline owdi  United States
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That depends entirely on your application. What is the power supply for?

Dan
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Old 21st February 2007, 07:27 PM   #5
beerman is offline beerman  United States
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Chip amp for a 5.1 application: 5 LM3886s at 4ohms (28v rails seems to be the suggestion from NSC on their LM3886 page for 4ohm use) connected to a home theater PC.

The current debate raging in my head is whether or not to DIY the subwoofer amplifier and include it in the same box, or if I should use a commercially available plate amp. Either way, the sub wants a considerable amount of juice.
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