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Old 26th January 2006, 02:21 PM   #11
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i m posting the image for correctly using the diodes across the regulator ics

the diodes provide protection(they must not be reverse biased).
d1 and d2 ensure that the transients on the regulator o/ps do not drive the o/ps to a potential above their i/ps and cause damage to the regulators.
regulators may not turn on simultaneously,if such a condition occurs the o/p of the slower one may be driven to the potential of the faster one ,so d3 and d4 prevent this condition.

IN4007 or alike are sufficient.
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Old 26th January 2006, 02:32 PM   #12
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Originally posted by starushz
However in this cap suppose i have a large value cap at the o/p and it discharges. The diode will not protect the o/p of the regulator as it si reversed right? So doesnt it make the diode useless?

No. With the neg reg, if the cap discharges, the reg input is pos with respect to its output, and the diode shunts the cap discharge current away, as shown in the previous post.

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Old 26th January 2006, 02:46 PM   #13
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ok guys thanks alot. I understand now.
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