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#1 |
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diyAudio Member
Join Date: Jan 2004
Location: Hudiksvall
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Hello
I have made a PCB for a simple 317/337 PSU http://www.ettnet.se/~tobias/diy/opabuf/schema_psu.jpg On the PCB there's only a RC and not RCRC, one of this boards is gonna drive a one-channel OPA627/BUF634 combo @ +/-17V My question is: Is 15ohms a bit to high in the "RC"? should it be like 5ohms or something instead? Trannies would prpbably be 2x18VAC or 2x15VAC if the voltagedrop isn't to high. Cheers |
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#2 |
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diyAudio Member
Join Date: Nov 2004
Location: Gävle
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Hi
The size of the resistors set the LP-filter value for the RC combination, to knock out 50Hz, the lower values of R - the higher your low pass frequency cut-out gets. At 5 ohms, your -3 dB is at approx. 26 Hz, and at 15 ohms, it is 9 Hz. Quite a difference. Then of course, it is interesting to know how much current your the OPA627/BUF634 will draw, to minimize the losses in these resistors. |
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#3 |
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diyAudio Member
Join Date: Jan 2004
Location: Hudiksvall
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Hello Loial
Well the combo can put out about 250mA i guess but as it's gonna be used as a preamp for a chipamp the currentdraw would not be big. Hm, so a 2.5 ohms could work out fine then? but then it would be aiming for the 50Hz ripple? Thought I read that a higher value in an CRC would make a better overall PSRR (or what it's called) Thanks |
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#4 |
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diyAudio Member
Join Date: Nov 2004
Location: Gävle
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I would say you should use a resistor as large as possible, to cut of the 50 Hz from the voltage.
Though a larger resistor also means larger voltage drop... If it is used as a preamp there should'n be a problem using the 15 ohm resistors. |
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#5 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi,
since you are deleting the second RG, then I suggest that you add the two inline resistors together to give 30R (or use 33R). The time constant is only 18mS (15R) and 40(33R) so there is some leaway to increase R further. Maybe try 47R. At 10mA draw it loses half a volt. One opamp could draw 20 to 50mA into low loads at peak and volts lost before reg would be 2.4Volts at peak current (15Vpk into 400R). |
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#6 |
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diyAudio Member
Join Date: Jun 2005
Location: San Diego, CA
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What you have is two consecutive first order RC filters..
THe result is a DOUBLE POLE filter..with a -40dB rolloff from the POLE.... In your case the pole is at 8.8Hz.... You are trying to filter 100Hz not 50Hz...since you have a full-wave bridge..... You already know that you will be -40dB down at 88Hz..so figure it at 100Hz.... Don't sweat over this.... The input cap is figured based on the minimum DC input voltage to the linear regulator...since you have a PEAK of the ripple is refered to MAX voltage..the cap size you choose will change the Vmin of the ripple.... Also too big of a cap will shorten the conduction time/angle on the diodes and increases current peaks... The EMI and Power factor need to be assessed... Chris |
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#7 | |
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Electrons are yellow and more is better!
diyAudio Member
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Quote:
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/Per-Anders (my first name) or P-A as my friends call me Tube Buffered Gainclone in work |Thread |
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#8 |
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diyAudio Member
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These regulators and op-amps already show pretty high PSRR figures at low frequencies so I think there is not much left to improve. Humm due to rail ripple will be probably below noise floor anyway.
Poles may be more useful when placed around 150..300Hz, so that line harmonics and EMI get attenuated without sacrifying too much efficiency. Such poles are obtained with R values in the range 2r2..4r7 for 1200uF capacitors. Splitting resistance between +Vcc/-Vcc and ground may be useful for EMI isolation. |
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#9 |
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diyAudio Member
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you might find that it is less expensive, (it will also take up less real estate) -- to use a tracking pre-regulator -- National will show you how in the LM317 product folder -- a tracking pre-regulator was used in the later versions of the Super-Regulator.
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