smps transformer

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Hello I need help

I'm making an inverter welder
Transformer data:
E 71/33/32 N87
For 50v output
I have 13 primary turns 0.67mm x 20 wires and 8 secondary turns 0.67mm x 58 wires.
The problem is:
The secondary coil I want to wind with copper foil not with copper wires
So how can I calculate how many turns of copper foil I have to make? And dimensions of copper foil? Please help
 
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for secondry i have 0.67mm x 58 wires

what size of foil i use please help i'm not understanding


and thanks for quickly reply in other forums they reply after 1 month

Your secondary wire is 0.67mm in diameter ?
so cross section area (csa) of one strand is pi*d*d/4 = 0.35 mm2, right ?
0.35 mm2 times 58 strands = approx. 20 mm2
so you need at least 20 square mm cross section area of your foil.

Thermal properties of foil may be different, I don't know.
Also, if inverter frequency is high, multiple strands of wire is much better because of skin effect.
 
Last edited:
Your secondary wire is 0.67mm in diameter ?
so cross section area (csa) of one strand is pi*d*d/4 = 0.35 mm2, right ?
0.35 mm2 times 58 strands = approx. 20 mm2
so you need at least 20 square mm cross section area of your foil.

Thermal properties of foil may be different, I don't know.
Also, if inverter frequency is high, multiple strands of wire is much better because of skin effect.

you are a genius man thank you very very much

but one other thing i calculated all with this software diysmps

but one thing is not clear if i have to wind for first primary or secondry turns
 
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