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Old 3rd December 2012, 07:09 PM   #1
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Default smps transformer

Hello I need help

I'm making an inverter welder
Transformer data:
E 71/33/32 N87
For 50v output
I have 13 primary turns 0.67mm x 20 wires and 8 secondary turns 0.67mm x 58 wires.
The problem is:
The secondary coil I want to wind with copper foil not with copper wires
So how can I calculate how many turns of copper foil I have to make? And dimensions of copper foil? Please help

Last edited by Pano; 3rd December 2012 at 07:18 PM. Reason: changed case
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Old 3rd December 2012, 07:14 PM   #2
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Exactly the same number of turns as for wire.

Wire CSA is the same regardless of if it is foil or wire.
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Old 3rd December 2012, 07:20 PM   #3
Pano is offline Pano  United States
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Please do not use all caps when posting. Read the forum rules, they are here.
I have fixed your post.
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Old 3rd December 2012, 07:27 PM   #4
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Quote:
Originally Posted by KatieandDad View Post
Exactly the same number of turns as for wire.

Wire CSA is the same regardless of if it is foil or wire.
for secondry i have 0.67mm x 58 wires

what size of foil i use please help i'm not understanding


and thanks for quickly reply in other forums they reply after 1 month
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Old 3rd December 2012, 07:30 PM   #5
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Default help

Quote:
Originally Posted by KatieandDad View Post
Exactly the same number of turns as for wire.

Wire CSA is the same regardless of if it is foil or wire.
for secondry i have 8 turns of 0,67mm x 58 wires

what size of foil have to use please help im not understanding
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Old 3rd December 2012, 07:36 PM   #6
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Originally Posted by Pano View Post
Please do not use all caps when posting. Read the forum rules, they are here.
I have fixed your post.
sorry
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Old 3rd December 2012, 07:47 PM   #7
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Why do u want to use foil? That is only used in planars where sw-freq is very high, b/c that requires low inductance and few turns. It will likely become very capacitive with that many turns.
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Old 3rd December 2012, 07:52 PM   #8
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Quote:
Originally Posted by SemperFi View Post
Why do u want to use foil? That is only used in planars where sw-freq is very high, b/c that requires low inductance and few turns. It will likely become very capacitive with that many turns.
i want to make this

Welding inverter 100A
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Old 3rd December 2012, 08:01 PM   #9
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Quote:
Originally Posted by jagdeepsingh2 View Post
for secondry i have 0.67mm x 58 wires

what size of foil i use please help i'm not understanding


and thanks for quickly reply in other forums they reply after 1 month
Your secondary wire is 0.67mm in diameter ?
so cross section area (csa) of one strand is pi*d*d/4 = 0.35 mm2, right ?
0.35 mm2 times 58 strands = approx. 20 mm2
so you need at least 20 square mm cross section area of your foil.

Thermal properties of foil may be different, I don't know.
Also, if inverter frequency is high, multiple strands of wire is much better because of skin effect.
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Last edited by payloadde; 3rd December 2012 at 08:03 PM. Reason: typo
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Old 3rd December 2012, 08:45 PM   #10
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Quote:
Originally Posted by payloadde View Post
Your secondary wire is 0.67mm in diameter ?
so cross section area (csa) of one strand is pi*d*d/4 = 0.35 mm2, right ?
0.35 mm2 times 58 strands = approx. 20 mm2
so you need at least 20 square mm cross section area of your foil.

Thermal properties of foil may be different, I don't know.
Also, if inverter frequency is high, multiple strands of wire is much better because of skin effect.
you are a genius man thank you very very much

but one other thing i calculated all with this software diysmps

but one thing is not clear if i have to wind for first primary or secondry turns
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