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Old 19th August 2012, 12:43 PM   #671
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Quote:
Originally Posted by jacco vermeulen View Post
I have a couple of original late '80s bought Partridge output transformers looking at me, they're saying they'd like a CLC to feed them.
I dun know these transformers. What is CLC? How heavy are they?
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Old 19th August 2012, 12:47 PM   #672
AndrewT is offline AndrewT  Scotland
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CLC is the circuit that smooths the output of the rectifier.
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Old 19th August 2012, 12:49 PM   #673
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Originally Posted by liching1952 View Post
Power= U^2/R or I^2.R so its all the same.
No.
It's not the same, as he stated.
you are looking at resistance as the sole load and ignoring all parasitics.
You are wrong on at least two counts.
The load is not pure resistance.
The supply is riddled with parasitics.
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Old 19th August 2012, 12:55 PM   #674
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Quote:
Originally Posted by AndrewT View Post
No.
It's not the same, as he stated.
you are looking at resistance as the sole load and ignoring all parasitics.
You are wrong on at least two counts.
The load is not pure resistance.
The supply is riddled with parasitics.
Thank you Andrew.
I have a feeling that liching1952 just feels like arguing for the sake of it.
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Old 19th August 2012, 01:05 PM   #675
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Quote:
Originally Posted by liching1952 View Post
I dun know these transformers.
Partridge was a British transformer company.
They weigh a standard bag of potatoes each, go by the name TH4663, afaig there are still a couple of shops that sell them to silly buggers for $1000.

(but if weight is your thing, how about 30lb each Partridge really high current chokes i wrenched out of pro-medical jogg/walking machines ?)
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Old 19th August 2012, 01:09 PM   #676
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Quote:
Originally Posted by AndrewT View Post
No.
It's not the same, as he stated.
you are looking at resistance as the sole load and ignoring all parasitics.
You are wrong on at least two counts.
The load is not pure resistance.
The supply is riddled with parasitics.
Basic physics says, only the resistive part of the load absorbs power, the imaginary part doesnt.
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Old 19th August 2012, 01:11 PM   #677
DF96 is offline DF96  England
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Quote:
Originally Posted by gootee
Similarly, for any power amplifier with a linear PSU there is a lowest reservoir capacitance, below which the amplifier will not meet its specifications. How can we calculate the value of that capacitance?
I'm not certain that is true. If you increase the quiescent supply rail voltage enough, it doesn't matter how much it droops (assuming PSRR is not an issue) so you can have a small cap. Your stored energy will increase because of the higher voltage. What you can do is calculate the smallest cap required, given a stated Vdc (exceeding Vpk by whatever margin you deem helpful). You can also calculate the minimum stored energy (see my earlier post) but that merely lets you then choose C (given Vdc) or choose Vdc (given C).

I suspect you are all looking for the gold at the end of the rainbow: there is not an optimum value for C or Vdc, although there may be an optimum combination. Total 'AC in' to 'sound out' efficiency may be a useful parameter, as raising Vdc unnecessarily reduces efficiency.
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Old 19th August 2012, 01:15 PM   #678
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Quote:
Originally Posted by jacco vermeulen View Post
Partridge was a British transformer company.
They weigh a standard bag of potatoes each, go by the name TH4663, afaig there are still a couple of shops that sell them to silly buggers for $1000.

(but if weight is your thing, how about 30lb each Partridge really high current chokes i wrenched out of pro-medical jogg/walking machines ?)
Weight more or less gives an indication how they will perform at the lower end. If they are good, so build a good amp with KT100 or so. And what do you mean CLC. AndrewT wrote that it is a circuit smoothing thd power. Does it has anti hum windings for this purpose?
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Old 19th August 2012, 01:18 PM   #679
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huh 1000 bugs for 1 transformer. Better buy a good 2nd hand profesional made Beard P100 or Quad for 1500 or so.
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Old 19th August 2012, 01:26 PM   #680
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Originally Posted by Nico Ras View Post
I also suppose that you have never heard of power factor correction, specifically to counter this problem.
Yes am MSc but doesnt understand power factor correction so explain.
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