|
|||||||
| Home | Forums | Rules | Articles | Store | Gallery | Blogs | Register | Donations | FAQ | Calendar | Search | Today's Posts | Mark Forums Read | Search |
|
Please consider donating to help us continue to serve you.
Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving |
|
![]() |
|
|
Thread Tools | Search this Thread |
|
|
#1031 |
|
diyAudio Member
Join Date: Mar 2008
|
Tom, thats great work! Its been my pleasure to help, and I'm learning a lot.
I'm tickled pink you've sussed out the PU xfmr model. its a really, really powerful technique, and like all good tricks, has been around a long time. back before easily accessible computing, engineers had to think really, really hard. Oh the nomograms they created - Phillip Smith was just one of many brilliant engineers. another way to use the PU model is to ascertain bounds (eg derived from measurements over a range of xfmrs) on the PU resistances & leakage inductances. For example with mains transformers (too lazy to research so going from memory), leakage ranges from about 5% (high efficiency devices) to around 10%, with 15% being an upper bound** it'll be different for physically smaller devices though, due to the Surface Area to Volume ratio - e.g. efficiency of small induction machines is pretty bad, because they can get rid of the heat. again from memory, with < 1kW induction motors its common to find locked-rotor currents (in PU I_locked_rotor = 1/L_leakage) of about 500%, so around 20% leakage. thats a problem from a power loss perspective (plenty of industrial plants have hundreds of small motors & drives), and the newer high-efficiency machines are more like 5%. Which of course means the locked-rotor current are now more like 2000%, creating a whole new set of problems. I have no idea what xfmrs most people actually use, but it would be nice to assemble a repository of xfmr models. its straightforward to hack up a spreadsheet implementing your xfmr measurement protocol, and then Per-Unitising the results. the real trick is getting the xfmrs to measure. Anybody know a friendly supplier that'll lend out samples to have them characterised? ** I once had a chat with some engineers at ABB in New Plymouth, and they showed me a couple of 14% xfmrs shipped in from South America. I forget how many MVA, but they were about 10' x 10' x 10'. apparently it was a comms screwup, and the bosses were not happy. they offered to sell them to me for beer money..... errata: my last name is singular, not plural. I dont mind at all, but am a raging pedant (here's a fun trick: tell a pedant to stop being so "pendantic" and watch their head explode)). its hilarious though - I usually say Given, as in "given a stupid name thats also in the dictionary" and most people still write Gibbon. Maybe I should use my Chinese name instead..... |
|
|
|
#1032 |
|
diyAudio Member
|
Yes, DF. But also, we never did hope that there was one absolute minimum capacitance value. Actually, I don't think Nico even mentioned "minimum". That was just something that I thought we should try to find an equation or rule of thumb for, to try to start to find some bounds around what Nico had asked for, which was more like "Can we come up with a rule of thumb for how much capacitance should be used?".
Later today, hopefully, I will try to find out how that "separation voltage" changes for different combinations of Vrms rating, Rload, Pout, and VA rating. It might be nice to be able to understand exactly how it arises and how we might calculate it (which might be obvious but I haven't had time to think about it except in terms of simulations, for quite some time now), but maybe it would not be very useful unless we also had an easy way (besides simulations) to know the minimum rail voltage. I have been hoping that using the square wave test signal will almost-directly translate into easy calculation methods using assumed-constant DC peak load current. It's one of many things that should be easy and obvious to figure out but which I simply haven't gotten to, yet. There are definitely differences between the square wave and the constant load current cases, such as modulation of the rail voltage amplitude at the difference frequency of the rectifier output and the square wave's repetition rate, and some other variations caused by the signal rises and falls. But since we are just looking for generic rules of thumb, we might be able to just add some small "safety margin" to account for those. And I have only been talking about finding the bare minimum C. But that's probably not what C "should be used", anyway. It might come down to some minimum acceptable distortion level, in terms of the "normal" type of distortion, not the overt type where the rail voltage and the signal voltage get too close together and cause obvious protrusions to grossly deform the output waveform. Recapping: That overt distortion is what I was using to find what I called "the absolute minimum C value". But after C is large-enough and that overt type of distortion is impossible, there is still an image of the rail voltage in the ideally-flat tops and bottoms of the square waves, that is what I referred to as the "normal" type of distortion. We can make that normal type of distortion smaller by adding more C. It appears to approach an asymptote as C gets very large. So there is apparently a C value that is large-enough, after which it doesn't improve very much if more C is added. Anyway, the "absolute minimum" required C, in each case, where the overt distortion disappears as C increases, and the accompanying almost-constant vrailmin - vsignalmax voltage difference, appear to mark the region where the plot of the normal type of distortion versus C "turns the corner" from mostly vertical toward mostly horizontal and begins approaching the asymptote. So I'm hoping that we can find that something closely related to the approximate DC-type capacitance and ripple equations can be used (in light of the square wave simulation data) to predict the absolute minimum C and/or the minimum vrailmin minus vsignalmax voltage, based on a given Rload, Pout, and xfrmr Vrms and VA ratings, and that we can also then find a simple rule for knowing how much C to add to that minimum, to also take us to a minimum-acceptable level of the normal type of distortion, down on the flatter part of the distortion vs C plot. Cheers, Tom |
|
|
|
#1033 |
|
diyAudio Member
|
Hi All,
Tom: You certainly did a great job, I do not think that others have gone so far as to with the models in the simulation. I followed (perhaps not very well) your work, I am with out a doubt, whereas the AC line is not perfectly sinusoidal, we know the reason of inductive loads, reactive, many big industrial capacity etc. see for example, ac1-ac2 is the secondary transformer, V-in (on main capacitor cell, in relation to the load 12Amp burst 1Khz. with duration of 20mS. there is a hole of energy is not in phase with the ac line I think. you can show like these on your model? it is simple monitor of ac-line, main capacitor, voltage rail on power devices. regards |
|
|
|
#1034 |
|
diyAudio Member
|
My apologies, Terry! I am usually the most-pedantic person around, wherever I am. And I am always slightly startled when I realize I've made an error like that. But it seems to have helped me try to learn to be more humble and human, over the years. At this point I prefer to believe that I am just more-exhausted than usual.
Anyway, in the context of future internet searches for your name, when you're even more famous than you are now, the following might serve as a small Rosetta Stone to help mitigate my error. I think that my error is confined to only diyaudio.com, where i have, several times, referred to Terry Given erroneously as Terry Givens. Cheers, Tom Gootee |
|
|
|
#1035 |
|
diyAudio Member
Join Date: May 2007
|
The smallest difference between rail voltage minimum and output peak maximum depends on the details of the output stage, and may vary slightly with the load resistance. In the case of your simulated output there are three Vbe drops, but also drops across the resistors - which will depend on BJT current gain. In some cases the resistors will have their value divided by the current gain, rather than setting a fixed voltage drop.
As you mention, even after gross clipping has been eliminated there may still be some 'ghost' of the ripple imprinted on the signal. That is down to the PSRR of the output stage, which it ought to be possible to estimate (even if only crudely), but it will depend on output stage architecture so no general rule of thumb will be possible. Fortunately NFB will help with this. |
|
|
|
#1036 | ||
|
diyAudio Member
|
Quote:
Quote:
I don't understand exactly what you are suggesting but I think that I can answer your question. In the simulation model, we can add connections and components at any point in a circuit. One component we can add is a voltage or current source ( or a circuit including them). And they can be driven or controlled in extremely-general ways, such as by equations, or by equations involving parameters from other parts of circuits. I am confident that we could devise a way to generate a close math to the burst you showed. And we can insert a voltage or current source into a conductor, anywhere, or connect it however we need to, in order to arithmetically sum the burst with that conductor's voltage or current. Regards, Tom |
||
|
|
|
#1037 |
|
diyAudio Member
|
Thank you for reply,
certainly my English does not help me. well, as you say, I agree, also I make models when I need it. I suppose that you have your complete model of transformer, rectifier and main capacitors (I think you have this) Now it is obvious that you have created a load (I hope dynamic) amplifier or as burst as you said. Now, I ask you to show the tracks in points. ac on the secondary, on main filter capacitors, and on load. as I have shown in my last post. |
|
|
|
#1038 |
|
diyAudio Member
|
I have on several occasions called Frank Fred, now that is a blunder of note!
__________________
Kindest regards Nico |
|
|
|
#1039 | |
|
diyAudio Member
|
Quote:
I have been running around doing unrelated tasking, so far today. So I haven't had time to study anything here on diyaudo, yet. (And my previous posts today were from my iphone.) I think that the only part that I don't understand is where and what the burst is. What causes it? Is it a current that the load is trying to draw? Or is it coming into the primary of the transformer as interference on the AC Mains? Or... what? Tom |
|
|
|
|
#1040 |
|
diyAudio Member
|
|
|
![]() |
| Thread Tools | Search this Thread |
|
|
Similar Threads
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Valve power supply - How to size transformer? | SanderW | Power Supplies | 25 | 4th January 2013 04:12 PM |
| How do you calculate choke size in a power supply? | Original Burnedfingers | Tubes / Valves | 25 | 5th January 2012 12:23 AM |
| power supply bypass cap size | BigE | Power Supplies | 11 | 5th July 2011 02:59 PM |
| Power Supply Case Size | diymixer | Power Supplies | 1 | 10th October 2010 05:47 AM |
| What size power supply should I get for repair work? | spooney | Car Audio | 3 | 6th December 2007 11:50 PM |
| New To Site? | Need Help? |