Just multiply the E (in V/m) by the distance (in m, of course) between the plates.
I figured as much. So 1V/cm across say 15cm is really 15 Volts.
No. 1V/cm is the strength of the electric field. If this field strength is maintained over a distance of 15cm then you will get a potential difference of 15V. Two different measurements of two different things: electric field and potential.
Its like the difference between the height of a hill and the slope. Both tell you something about the hill, but they tell you different things so are measured in different units.
Its like the difference between the height of a hill and the slope. Both tell you something about the hill, but they tell you different things so are measured in different units.
You don't, an electric field is an electric field, if you want to know volts you need to measure volts.Hello
Did not know where else to post this question - how do I translate the strength of an electric field say across the plates of a capacitor from say 1V/cm to something more common, eg Volts?
Thanks
Akis
Yes, though most practical applications are more likely to be measured in v/umI figured as much. So 1V/cm across say 15cm is really 15 Volts.
Dear Akis - look on the problem in a way that the E is like the slope of the hill and the V is like the height. It will be all much easier to understand.
Its like the difference between the height of a hill and the slope.
- Status
- This old topic is closed. If you want to reopen this topic, contact a moderator using the "Report Post" button.
- Home
- Amplifiers
- Power Supplies
- Electric fields