Iron Core Transformer Formula - Page 5 - diyAudio
Go Back   Home > Forums > Amplifiers > Power Supplies

Please consider donating to help us continue to serve you.

Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving
Reply
 
Thread Tools Search this Thread
Old 24th November 2011, 01:51 AM   #41
diyAudio Member
 
JOHN BALI's Avatar
 
Join Date: Jun 2010
Location: Near the Mountain
Quote:
Originally Posted by Tony View Post
and i am waiting for you to give the core dimensions, core area is you can please....hard to tell from the photos....

i do not give credence to any label on the traffo alone.......
Sorry for that , this is the core area size
no1 = 2.5cm * 4.5cm = 11.25cm
no2 = 3.2cm * 5.3cm = 16.96cm

& toroid = 2cm * 4.5cm = 9cm
Attached Images
File Type: jpg DSC03748.JPG (210.2 KB, 225 views)
File Type: jpg DSC03751.JPG (199.5 KB, 208 views)
File Type: jpg DSC03752.JPG (162.0 KB, 183 views)
  Reply With Quote
Old 24th November 2011, 02:07 AM   #42
diyAudio Member
 
JOHN BALI's Avatar
 
Join Date: Jun 2010
Location: Near the Mountain
Quote:
Originally Posted by pieter t View Post
A low B transformer will stay cool, but also stray fields will be minimal (two coil c-core transformers have already an advantage over EI), and the transformer will be more quiet; all these factors are somehow interrelated.
low B = bellow 1T?
I don't know how it looks of that C-core trafo,
do you have the picture of that kind of trafo?
what its size & VA ratting too
I just wanna know
  Reply With Quote
Old 27th November 2011, 04:19 PM   #43
diyAudio Member
 
JOHN BALI's Avatar
 
Join Date: Jun 2010
Location: Near the Mountain
Quote:
Originally Posted by JOHN BALI View Post
Thanks to all reply,
now I can recalculate every things, every thinks too
After recalculate I realize all my question has been answered



So here the formula + new formula:
for 50 Hz operation

@ B = 1T & E I core

N = 45 * U / A

@ B = 1.6T & toroidal core

N = 28.125 * U / A

for 60Hz operation

@ B = 1T & E I core

N = 37.5 * U / A

@ B = 1.6T & toroidal core

N = 23.4375 * U /A

Thanks for this formula
B = 50/f x 45 / (A x N) x U
f = frequency in Hz
U = rms value of voltage in V
A = magnetic core cross-section in cm
B = flux density amplitude in T(tesla)
N = number of turns
Note : B can be vary from what material we use to make transformer

Then for the VA ratting we can see from those attachment
also from RDH3 VA = (5.58 * A) or write like this VA = (5.58 * A) * (5.58 * A)
I hope No mistake from all that formula that I make
So next step is make it !!!

Thanks for all
Andrew T.
Tony
KatieandDad
pieter t
alexcp
zigzagflux
johansen

GBU
PEACE
Attached Images
File Type: png xformer.png (6.7 KB, 159 views)
File Type: gif tfrstep4.GIF (151.5 KB, 169 views)
Attached Files
File Type: doc Wire Number 1-40.doc (93.0 KB, 41 views)

Last edited by JOHN BALI; 27th November 2011 at 04:44 PM.
  Reply With Quote
Old 28th November 2011, 11:46 AM   #44
AndrewT is online now AndrewT  Scotland
diyAudio Member
 
Join Date: Jul 2004
Location: Scottish Borders
You can check the primary winding before you add on the secondary winding/s

Use a Variac to supply 0Vac to {maximum+5% of mains voltage} to the primary winding.
At each Primary Voltage measure the Primary Current. Be very careful, you are working with Mains Voltage. no pets, no children, no nagging wife. A helpful over the shoulder supervisor is useful.

Plot Primary current against Primary voltage. You should get an S curve. The bottom part of the S should straighten up at a quite low Primary voltage, maybe of the order of 10Vac to 20Vac.
The top part of the S (where Primary Current increases disproportionately with small increase in Primary Voltage) should occur as you reach maximum test voltage.
If the curve starts asymptotically approaching horizontal at well below the normal mains primary voltage, then from what I read and have tested you have too few turns on the primary winding. Now is the time to modify the Primary Ampere Turns.

I have repeatedly asked this question in transformer threads, but none of the "experts" have given a clear or even any answer !
__________________
regards Andrew T.
  Reply With Quote
Old 4th December 2011, 01:27 AM   #45
AJT is offline AJT  Philippines
diyAudio Moderator
 
AJT's Avatar
 
Join Date: May 2003
Location: Palatiw, Pasig City
Hi JOHN BALI,

any updates? please post pictures when you are done...seems you have all that you'll ever need, all that remains is for you to actually build something....as always, safety first.....good luck...
__________________
the best advertisement for a good audio design is the number of diy'ers wanting to build it after all the years....never the say so of so called gurus....
  Reply With Quote
Old 4th December 2011, 01:59 PM   #46
diyAudio Member
 
JOHN BALI's Avatar
 
Join Date: Jun 2010
Location: Near the Mountain
Not build anything yet ...
hope I have some more extra time,
to made
cool 300VA EI transformer,
but only use what I have here
I will post pictures & step by step, when I'm done


This one is trafo I have been made earlier
ImageShack® - Online Photo and Video Hosting
& this was how I winding the primary with double & same wire
to form input AC 110V in * 2 because easier to wind this way
but for safety it is not so good, better to use single 220V input
with good isolated per winding's layer
ImageShack® - Online Photo and Video Hosting
I guest its 500VA but its only 300VA .


Thanks
GBU & PEACE
Attached Images
File Type: jpg dsc03709p.jpg (81.9 KB, 135 views)

Last edited by JOHN BALI; 4th December 2011 at 02:17 PM.
  Reply With Quote
Old 5th December 2011, 04:54 PM   #47
diyAudio Member
 
KatieandDad's Avatar
 
Join Date: Nov 2011
Location: UK
Yawn - This has been discussed to death and back.
  Reply With Quote
Old 6th December 2011, 03:50 AM   #48
diyAudio Member
 
andrewlebon's Avatar
 
Join Date: Feb 2008
hi john
greetings sorry for not replying as i was out yesterday...this is my core and winding details...just want to know roughly power of toroidal as i have no idea what it's power is because a transformer 50 0 50 AC had burnt out and came for repairs we just counted the turns and SWG of wire and this is what data i used to wind my toroidal transformer by hand..need your help

Warm Regards
Andrew Lebon
Attached Images
File Type: jpg BILD0999.JPG (404.8 KB, 60 views)
File Type: jpg BILD1000.JPG (456.3 KB, 55 views)
  Reply With Quote
Old 6th December 2011, 10:52 AM   #49
diyAudio Member
 
JOHN BALI's Avatar
 
Join Date: Jun 2010
Location: Near the Mountain
Quote:
Originally Posted by andrewlebon View Post
hi john
greetings sorry for not replying as i was out yesterday...this is my core and winding details...just want to know roughly power of toroidal as i have no idea what it's power is because a transformer 50 0 50 AC had burnt out and came for repairs we just counted the turns and SWG of wire and this is what data i used to wind my toroidal transformer by hand..need your help

Warm Regards
Andrew Lebon
I will try to answer ...
For primary no 18 SWG (see attachment, on table's right side, to get diameter in mm [* 25.4])
diameter is 0.0480 inch = 1.2192 mm (please measure your wire's diameter for sure)
wire area = 3.14 / 4 * (diameter)
----------= 0.785 * (1.2192 * 1.2192)
----------= 1.167 mm
max amps for S = 2.82A/mm ---> 1.167 * 2.82 = 3.29A
max amps for S = 5A/mm ------> 1.167 * 5 = 5.83A
so V/A ratting for 220 volt input = 724VA & 1287VA
there are 2 V/A ratting
724 is safe rating, if we draw 724VA, the trafo will be quiet cool
1287 is max rating, we can draw 1287 but the trafo will be hot

for secondary no 16 SWG
diameter is 0.0640 inch = 1.6256 mm
wire area = 2.074 mm
max amps for S = 2.82A/mm ---> 2.074 * 2.82 = 5.84A
max amps for S = 5A/mm -------> 2.074 * 5 = 10.37A
V/A ratting for 100volt(50-0-50) output = 584VA & 1037VA max

I guess its good to keep VA rating of secondary less than primary, but please correct if I wrong.
I'm not trafo expert

Okay, now we enter the data to my formula...
but I don't know your mains voltage
your core area A = (16.5 - 7.5) * 4 = 36cm
for 220volt 50Hz & toroid core
N = 28.125 * U / A
= 28.125 * 220 / 36
= 172 turns
for 220volt 60Hz
N = 23.4375 * U /A
= 23.4375 * 220 / 36
= 143 turns

Now we can see there is so big difference...
my formula say 172/220 = 0.78 turn per volt
but your data is 2 turns per volt
Where do this data come from? Is this core was a working trafo but somehow it melt down?
This really make me confuse, anybody help?

note: my toroid that I built based on "Automatic AC Voltage Regulator (Stavolt)" with same core size.
I open & calculate turn per volt of that stavolt to make my own toroidal trafo, then I calculate with my formula and the results are similar.
I also have one 2000VA(mark on the box) toroidal auto-transformer, not check data inside yet.

Now I'm also need any help, any reference will be welcome



Regards
Attached Images
File Type: jpg AWG TABLE.jpg (817.4 KB, 173 views)
__________________
Thank you, I wish you happy
peace & G B U
  Reply With Quote
Old 6th December 2011, 12:47 PM   #50
AndrewT is online now AndrewT  Scotland
diyAudio Member
 
Join Date: Jul 2004
Location: Scottish Borders
Hi John,
I have checked the top half of your post, down to
Quote:
I'm not trafo expert
Everything you have shown is correct so far.

You ask about output VA and input VA.
I suggest you assume an efficiency for the transformer.
Let's say it's 95%. The maximum total output from all the secondary windings (based on the 2.82A/sqmm) will be 0.95 * 724 = 688VA.
Your 50+50 16swg @ 5.84Aac uses up 584 of those available secondary VAs. You have 104VA spare.
You can add extra turns to use that up. Or add extra windings to use that up. Or you can estimate the worst case VA loading conditions for a range of mixed voltage and current windings and pick out the worst operating condition and set that to use the whole 688VA available from the secondary.
Let's suppose you have some continuous current windings using 200VA and some ClassAB windings that normally run at 150VA but will increase to 700VA when testing to maximum output power. The total maximum load on the secondary will be 900VA while testing.
You can make a design design based on experience and measurement of how the transformer will operate when delivering half maximum power for 90% duty and full maximum power for 10% duty.
The effective total power is very approximately 200VA + 0.9*50%maxP VA + 0.1* 100% maxP VA.
We already know the 100% maxP VA = 700VA as above.
Let's assume the 50% maxP VA is >350VA try 450VA.
the likely worst case secondary VA is ~~~ 200 + 0.9*450 + 0.1*700 = 675VA. Just below the guesstimated 95% efficiency prediction.
You as designer can now build the transformer and the amplifier and test/measure it's performance. Since this is a new test of a new prototype you embed a few thermocouples in the core and primary winding and secondary windings and monitor operating temperatures for the worst case "real operating" conditions. When you are satisfied that your prototype is behaving as predicted or you have altered your model to fit with your test measurements then you can start production of your amplifier.
We as one or two off prototype builders don't do that thorough design exercise. We use our and others' experience to guide us to a reasonable set of estimates that give us reasonable model from which we make our predictions.

There is nothing wrong with having 5kVA of secondary windings on a 1kVA transformer, if you the builder/user know that you can never overheat the transformer with your intended usage nor exceed it's safety ratings during your worst case senarios.

Some ways of helping to ensure you don't inadvertently miss-use your amplifier and/or transformer is to fit fuses that blow if the target/modeled operating conditions are exceeded.
Close rated fusing is just one example. Output IV limiters are another. Heatsink temperature sensors/switches. It's a long list.

I have read and re-read your second part of the post.
I think your 0.78T/V is correct.
I don't know where 2T/V comes from either.
But I suspect the difference is something to do with you using
Quote:
N = 28.125 * U / A
and 2T/V using a different constant for a different steel. But a data chart that does not specify the conditions with which it is compatible is worse than useless. It is potentially dangerous.

BEFORE, one applies a chart, or nomogram, or other empirical data to a design situation one must ensure that the conditions are appropriate. If no conditions are specified, be it on your own head when it bites you !!!!
__________________
regards Andrew T.

Last edited by AndrewT; 6th December 2011 at 01:02 PM. Reason: as eg of checking data, I compared the AWG chart to SWG chart to see if 1.2192mm & 1.6256 were close to my reference charts.
  Reply With Quote

Reply


Hide this!Advertise here!
Thread Tools Search this Thread
Search this Thread:

Advanced Search

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off


Similar Threads
Thread Thread Starter Forum Replies Last Post
Where you buy iron transformer core for DIY audio transformer tarsik Tubes / Valves 10 27th December 2011 08:15 PM
Which, Foil Air Core or Iron Core Inductors slhijb Multi-Way 16 20th November 2009 03:12 AM
Solen Air core inductors, Hammond Iron core. gnomus Swap Meet 0 30th July 2004 01:28 AM
Iron Dust Core Transformer Hemal Car Audio 0 7th June 2004 03:43 PM
Air core vs Iron core Ilianh Multi-Way 5 2nd January 2003 01:36 PM


New To Site? Need Help?

All times are GMT. The time now is 12:55 PM.


vBulletin Optimisation provided by vB Optimise (Pro) - vBulletin Mods & Addons Copyright © 2014 DragonByte Technologies Ltd.
Copyright 1999-2014 diyAudio

Content Relevant URLs by vBSEO 3.3.2