Strong Ouzo stuff. Barbayanni is maybe even stronger. Comes from the same coastal town in the island of Lesvos.
An externally hosted image should be here but it was not working when we last tested it.
Could be a painful life....living in such a place....drinking ouzo...building heatsink axes for a living...
Is that where the strong women come from?
Lesbos or "Lesvos" island known for Ouzo and olive oil is home of the Lesbian people. Lesbos="Λέσβος" where β sounds like v. Because the ancient female lyric poet Sappho was very probably born there and her work centered around infatuations, love, and passions about both sexes but between women also, gay women got named after her place of birth no earlier than in the 19th century by scholars probably.
Hi all
Could the input voltage (or Security margin) be raised a few volts, if you put a R or some leds above Q102, to drop some volts?
Or would that decrease performance?
Peter
Not on a BIB board without hacking it. A resistor up to 4K7 messes with the IDSS and PSR a bit but its rather passable. Note the current on Q102's G to S resistor before, and lower its value to restore Id if you will see less after the Rdropper's addition. LEDS, you will need more botch space but they add less resistance, contributing their little new noise though.
ok, i have measured led: red ones are all mostly the same- 1.84 Uf and green too- 2 Uf
Jfet idss is beyond me (I have ebay gadget which measures them but it is not Idss I suspect but general I value, for instance I=56mA and U=392mV, but It is probably gives nothing).
So If I take those reds (2) and greens (3) with 23 v after rectification I get
R101 of 10 R
R103 would be something like 3k5 and trimmer about 1k3
Jfet idss is beyond me (I have ebay gadget which measures them but it is not Idss I suspect but general I value, for instance I=56mA and U=392mV, but It is probably gives nothing).
So If I take those reds (2) and greens (3) with 23 v after rectification I get
R101 of 10 R
R103 would be something like 3k5 and trimmer about 1k3
With 4k7 above Q2, the current drops 1,5% (way less than the temperature drift from startup)
That doesn't seem to hurt performance ...
peter
Hi, sorry for troubling you.I have populated a Back in Black positive board using ifr 9610 (q301) and irf9530n(Q306) having a bit of trouble. Would like to try and solve it myself but are these calculations right?
From the pdf
I want 0.06amps at 28volt
so I need the regulator 70-150ma > what I need
I take a figure of 100ma
therefore the regulator must give 160ma
R301 sets the current
R301 current= R301 volts/ Resistance in ohms of R301
R301 volts= LED voltage forward drop-MOSFET VGS (from graph)
R301 volts= 5.8volts(three green leds)-4.5 (from graph on pdf last page)
R301 volts=1.3
so for 160ma I need : 1.3/0.16
R301 should be 8.125 ohms
ie an 8-10 ohm resistor will suffice
wattage rating of resistor is IR=.16*10=1.6
thus r301 is a 2 to 5 watt resistor at 8 to 10 ohm (8 to 10 ohm because it gives me a current setting in the 70-150ma "add on" to your desired current setting)
From the pdf
I want 0.06amps at 28volt
so I need the regulator 70-150ma > what I need
I take a figure of 100ma
therefore the regulator must give 160ma
R301 sets the current
R301 current= R301 volts/ Resistance in ohms of R301
R301 volts= LED voltage forward drop-MOSFET VGS (from graph)
R301 volts= 5.8volts(three green leds)-4.5 (from graph on pdf last page)
R301 volts=1.3
so for 160ma I need : 1.3/0.16
R301 should be 8.125 ohms
ie an 8-10 ohm resistor will suffice
wattage rating of resistor is IR=.16*10=1.6
thus r301 is a 2 to 5 watt resistor at 8 to 10 ohm (8 to 10 ohm because it gives me a current setting in the 70-150ma "add on" to your desired current setting)
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