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 15th November 2010, 12:59 PM #11 diyAudio Member   Join Date: Jul 2004 Location: Scottish Borders C=I D=4I E=2I F=3I B=F+2I=5I A=D+2I=6I This arrangement gives zero waste and more importantly gives equal flux per unit of width. If you need more window area, then you cannot have zero waste. But bigger window area can still match all the flux flows per unit of width. __________________ regards Andrew T. Sent from my desktop computer using a keyboard Last edited by AndrewT; 15th November 2010 at 01:06 PM.
 15th November 2010, 01:06 PM #12 diyAudio Member   Join Date: Oct 2010 Thank you so much for your clear answer. I just wonder if those give the best solution why in many cases : B#F+2I A-D#B-F thanks!
 15th November 2010, 04:23 PM #13 diyAudio Member     Join Date: Jan 2003 Ferrite cores are not stamped. Ferrite cores can be made in lots of funny shapes without scrap. But still, the middle leg of the E core is typically double the area of the outer legs, the I part and the back of the E to get the same flux density everywhere. That gives: E = 2I B = F + 2I A = D + 2I EIR cores are not comparable though, having a round center leg. What about them?
 15th November 2010, 05:35 PM #14 diyAudio Member   Join Date: Jul 2004 Location: Scottish Borders oops, I did not read "ferrite". Ignore all since it only applies to iron cored. __________________ regards Andrew T. Sent from my desktop computer using a keyboard
 16th November 2010, 06:07 AM #15 diyAudio Member   Join Date: Oct 2010 yep. In EIR core: the cross-section area also =2xthat of leg. I wonder if it is optimum solution for flux why in many cases B-F-I# I E=A-D#2I (it is not difficult to shape the core in these condition) and can you explain why ferrite core is different? Thanks!
 16th November 2010, 11:28 AM #16 diyAudio Member   Join Date: Nov 2010 Can anyone teach me how to calculate the effective magnetic path of a core? For PQ core, how can we determine it?

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