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25th September 2010, 05:10 AM
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#1 |
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diyAudio Member
Join Date: Jul 2010
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very simple question
Hi all,
i have very por basics so please solve the question and let me know how you did it. The circuit is attached with the thread. you need to find ? Vasu |
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25th September 2010, 05:18 AM
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#2 |
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diyAudio Member
Join Date: Mar 2007
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It would be 2.7v. A regular forward biased diode has a 0.7v drop. Schottkys can have as low as 0.2v drop depending on design.
__________________
"Fully on MOSFET = closed switch, Fully off MOSFET = open switch, Half on MOSFET = poor imitation of Tiffany Yep." - also applies to IGBTs! |
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25th September 2010, 05:58 AM
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#3 |
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diyAudio Member
Join Date: Jul 2010
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thanx...
it never stuck me...
i know of 0.7V drop. I am trying to build a and circuit using diode, and the output would be lower of the two inputs always. so was working on drops across the diodes. thankyou for prompt reply vasu |
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25th September 2010, 08:41 AM
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#4 | |
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diyAudio Member
Join Date: Dec 2009
Location: Italy
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Quote:
what is the impedance of the circuit when you measure? |
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25th September 2010, 09:30 AM
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#5 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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when 5V is at one end of the resistor and 2.7V is at the other end of the resistor you can calculate the current through the resistor and the diode.
[5-2.7] / 10k = 0.00023 = 230uA.
__________________
regards Andrew T. |
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25th September 2010, 10:36 AM
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#6 | |
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diyAudio Member
Join Date: Dec 2009
Location: Italy
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Quote:
Ah!...very thank, now I know this..  ...question from savu is not this. |
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