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Old 25th September 2010, 06:10 AM   #1
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Default very simple question

Hi all,

i have very por basics so please solve the question and let me know how you did it.

The circuit is attached with the thread. you need to find ?

Vasu
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Old 25th September 2010, 06:18 AM   #2
star882 is offline star882  United States
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It would be 2.7v. A regular forward biased diode has a 0.7v drop. Schottkys can have as low as 0.2v drop depending on design.
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Old 25th September 2010, 06:58 AM   #3
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Default thanx...

it never stuck me...
i know of 0.7V drop.

I am trying to build a and circuit using diode, and the output would be lower of the two inputs always.

so was working on drops across the diodes.

thankyou for prompt reply

vasu
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Old 25th September 2010, 09:41 AM   #4
AP2 is offline AP2  Italy
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Quote:
Originally Posted by mail2vasu2004 View Post
it never stuck me...
i know of 0.7V drop.

I am trying to build a and circuit using diode, and the output would be lower of the two inputs always.

so was working on drops across the diodes.

thankyou for prompt reply

vasu
Hi,
what is the impedance of the circuit when you measure?
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Old 25th September 2010, 10:30 AM   #5
AndrewT is online now AndrewT  Scotland
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when 5V is at one end of the resistor and 2.7V is at the other end of the resistor you can calculate the current through the resistor and the diode.
[5-2.7] / 10k = 0.00023 = 230uA.
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Old 25th September 2010, 11:36 AM   #6
AP2 is offline AP2  Italy
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Quote:
Originally Posted by AndrewT View Post
when 5V is at one end of the resistor and 2.7V is at the other end of the resistor you can calculate the current through the resistor and the diode.
[5-2.7] / 10k = 0.00023 = 230uA.
hi,
Ah!...very thank, now I know this..
...question from savu is not this.
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