very simple question
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mail2vasu2004
diyAudio Member

Join Date: Jul 2010
very simple question

Hi all,

i have very por basics so please solve the question and let me know how you did it.

The circuit is attached with the thread. you need to find ?

Vasu
Attached Files
 ex-1.pdf (13.9 KB, 37 views)

 25th September 2010, 05:18 AM #2 star882   diyAudio Member     Join Date: Mar 2007 It would be 2.7v. A regular forward biased diode has a 0.7v drop. Schottkys can have as low as 0.2v drop depending on design. __________________ "Fully on MOSFET = closed switch, Fully off MOSFET = open switch, Half on MOSFET = poor imitation of Tiffany Yep." - also applies to IGBTs!
 25th September 2010, 05:58 AM #3 mail2vasu2004   diyAudio Member   Join Date: Jul 2010 thanx... it never stuck me... i know of 0.7V drop. I am trying to build a and circuit using diode, and the output would be lower of the two inputs always. so was working on drops across the diodes. thankyou for prompt reply vasu
AP2
Banned

Join Date: Dec 2009
Location: Italy
Quote:
 Originally Posted by mail2vasu2004 it never stuck me... i know of 0.7V drop. I am trying to build a and circuit using diode, and the output would be lower of the two inputs always. so was working on drops across the diodes. thankyou for prompt reply vasu
Hi,
what is the impedance of the circuit when you measure?

 25th September 2010, 09:30 AM #5 AndrewT   R.I.P.   Join Date: Jul 2004 Location: Scottish Borders when 5V is at one end of the resistor and 2.7V is at the other end of the resistor you can calculate the current through the resistor and the diode. [5-2.7] / 10k = 0.00023 = 230uA. __________________ regards Andrew T.
AP2
Banned

Join Date: Dec 2009
Location: Italy
Quote:
 Originally Posted by AndrewT when 5V is at one end of the resistor and 2.7V is at the other end of the resistor you can calculate the current through the resistor and the diode. [5-2.7] / 10k = 0.00023 = 230uA.
hi,
Ah!...very thank, now I know this..
...question from savu is not this.

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