PA input voltage simple precision regulator
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SMourareau
diyAudio Member

Join Date: Mar 2010
Location: Paris
PA input voltage simple precision regulator

My spec.were:
• +/-40-60V input voltage
• +/- 17V 1% output voltage without triming
• 50mA of nominal current
• low noise, low output impedance, low ripple
• simple design
And after investigating several solutions, I had the following idea. Note that voltage reference and op amp are fed by output voltage. I still haven't tried this solution and would be interested to know if some one here had some experiments with something like this.

Device list:
RA1
Res.
9,09K

RA2
Res.
9,09K

RA3
Res.
3,65K

RA4
Res.
3,65K

RA5
Res.
5,23K

RA6
Res.
5,23K

RA7
Res.
20K

RA8
Res.
20K

RA9
Res.
9,09K

RA10
Res.
9,09K

CA1
Cap.
10u

CA2
Cap.
10u

CA3
Cap.
10u

CA4
Cap.
10u

CA5
Cap.
33pf

CA6
Cap.
33pf

ICA1
Op. Amp.

LT1677
ICA2
Op. Amp.

LT1677
DA1
Zener
8.2V

DA2
Zener
8.2V

DA3
Sh.Reg.
10V
LM4040
DA4
Sh.Reg.
10V
LM4040
TA1
Bjt

KSC2690
TA2
Bjt

KSA1220
Attached Images
 sym-regul.png (16.6 KB, 85 views)

 17th June 2010, 05:59 AM #2 RJM1   diyAudio Member   Join Date: Jan 2010 Location: Titusville, Fl. Well it would work but not with those resistor values. The ratio of the voltage divider network at the negative input of the op-amp (RA3/RA5) should be “1+(17(output voltage)/8.2(zener reference) )= 2.073”. Yours is “1+3.65k/5.23k = 1.697” which would give you an output voltage of 13.92V. One other thing is that the current through DA1 which is set by RA1 should be set to the zener test current of the diode which can be found on the diodes data sheet. With RA1 set at 9.09K the current through the zener is slightly less than 1ma which seems too low, this will lower the diode’s reference voltage.
 17th June 2010, 07:01 AM #3 SMourareau   diyAudio Member   Join Date: Mar 2010 Location: Paris Well excuse me for my device list which is particularly unclear. On the schematic there is two devices represented as zeners. In fact the voltage réference is not actually a zener it is an LM4040 10V shunt regulator which is suppose (according to its DS) to work very well with less than 1mA. Regards
 17th June 2010, 03:19 PM #4 RJM1   diyAudio Member   Join Date: Jan 2010 Location: Titusville, Fl. Yes but your DA1 and DA2 are the voltage references for you 17V and are listed in your device list as 8.2V zener diodes. Your LM4040's just let the pass transistor turn on enough to get voltage to your op-amp at start up so that it can then regulate to the 8.2V zener that you are using as a voltage reference to the op-amp for your 17V output. So in fact the voltage reference that you are using to compare you 17V to is the 8.2V zener diode and not your LM4040 10V shunt regulator.Or maybe your device list and your schematic don't match? Last edited by RJM1; 17th June 2010 at 03:21 PM.
 17th June 2010, 04:18 PM #5 SMourareau   diyAudio Member   Join Date: Mar 2010 Location: Paris Yes you are right the device is unclear and there is a mistake in it: the references to to the voltage reference and the zener are inverted.

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