Go Back   Home > Forums > Amplifiers > Power Supplies
Home Forums Rules Articles Store Gallery Blogs Register Donations FAQ Calendar Search Today's Posts Mark Forums Read

Please consider donating to help us continue to serve you.

Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving
Reply
 
Thread Tools Search this Thread
Old 6th March 2010, 11:30 PM   #1
opor is offline opor  Thailand
diyAudio Member
 
Join Date: Nov 2005
Default +15V pre-regulate for classD amp

From this circuit,it is +15V pre-regulate for classD amp . R114B and R115B are calculated base on -B=-50V . So if -B =-90V what should R114B and R115B be? And how to calculate?
  Reply With Quote
Old 6th March 2010, 11:37 PM   #2
opor is offline opor  Thailand
diyAudio Member
 
Join Date: Nov 2005
Sorry ,here is circuit.
Attached Images
File Type: jpg 15V pre-regulate.jpg (14.0 KB, 221 views)
  Reply With Quote
Old 7th March 2010, 02:39 PM   #3
mag is offline mag  Switzerland
diyAudio Member
 
Join Date: Jan 2008
Location: Chiasso
Hi opor,
For R115 is easy but for R114 it depens on how much current you need from the 15V.

with R115=15k and -B=-50V we can calculate the current in the zener diode.

Iz=(50V-15V)/15k=2.3mA.

Now let's keep 2.3mA in the zener diode and calculate R115 to have Iz=2.3mA at -B=-90V.

R115=(90V-15V)/2.3mA=33kohm.

R114 helps the transistor to dissipate the power, start with something like
2.2kohm and check the temperature rise of the resistor and the transistor.

Is this regulator used for the VCC supply of the IRS2092 IC?

Supposing that current needed from VCC is 25mA you will have the following
figures from power dissipation:

1: -B=50V Iout=25mA

P_R114=25mA*25mA*1kohm=0.625W (1W resistor is needed)
P_trans=Vce*Ic=(50V-25mA*1kohm-15V)*25mA=0.25W

2: -B=90V Iout=25mA

P_R114=25mA*25mA*2.2kohm=1.37W (3W resistor is needed)
P_trans=Vce*Ic=(90V-25mA*2.2kohm-15V)*25mA=0.5W

These calculations applies if Iout=25mA if it is more you need to select a proper value for R114.

Btw: if it is the IRS2092, don't even try to power it up at +/-90V, it will blow up. You need at least some totem poles drivers to drive the mosfets.
  Reply With Quote
Old 7th March 2010, 03:27 PM   #4
opor is offline opor  Thailand
diyAudio Member
 
Join Date: Nov 2005
Dear Mag,
Do you have any idea ,is this schematic work or not ? It is hard to get IRFB4020 .If I use IRFP250 instead . Which component I have to change?
Attached Images
File Type: gif miniXD_SCH.gif (33.0 KB, 186 views)
  Reply With Quote
Old 8th March 2010, 09:08 AM   #5
mag is offline mag  Switzerland
diyAudio Member
 
Join Date: Jan 2008
Location: Chiasso
Hi opor,
IRFP250 has much higher Qg compared to IRFB4020 (123nC vs 18nC).
On top of that is slower and also its body diode is slower.
Regarding conduction losses they are more or less equivalent (80mohm vs. 75mohm).

Looking at your schematics I have serious doubt about getting 700W rms at +/- 90Vdc on 4ohm load. A single pair of IRFB4020 (or even worse IRFP250) are not enough due to the high conduction losses.

On top of that driving the IRFP250 with it 123nC of gate charge needs for sure some external totem pole drivers in order to switch it reasonably fast. The drivers integrated in the IRS2092 are quite weak.

I suggest you to go on IRFB4227 which is the new generation of IRFB4020 with reduced Rds_on (19.7mohm) and reasonably fast switching characteristics.

I have tried to go to +/-50V with IRS2092 + IRFB4227 and I could easily get more than 250Wrms into 4ohm. I have tried also to connect two of these modules in bridge and I could get around 1kW into 4ohm with +/-50V rails.

Then after changing some components I have tried to increase the rails at
+/-80V and everything blow up... The IRS2092 has not enough drive current to switch the IRFB4227 reasonably fast when running at +/- 80V the swiching losses are huge and there is the possibility of cross conduction of the two mosfets.

You have to add two external totem poles or two mos drivers rated at at least 4A if you want to go at +/-90V with IRS2092. If you want to stay on IRFP250 use 2 of them in parallel and care at the driver.
  Reply With Quote
Old 8th March 2010, 04:17 PM   #6
diyAudio Member
 
Join Date: Dec 2008
Location: Shenzhen
regardless of the MOS-FET's which you use or if there will be used a totem-pole drivers or not, do not not exceed +-75V for supply rails or +-85 V in BTL mode. the voltage spikes and pumping effect will kill the ic.
  Reply With Quote
Old 26th March 2010, 04:52 PM   #7
opor is offline opor  Thailand
diyAudio Member
 
Join Date: Nov 2005
Hi Mag,

How about IRF640 and IRF540? Is it good for this design?
  Reply With Quote

Reply


Hide this!Advertise here!

Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)
 
Thread Tools Search this Thread
Search this Thread:

Advanced Search

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off


Similar Threads
Thread Thread Starter Forum Replies Last Post
Circuit Sanity Check: +15V, -15V, +9V Power Supply miallen Power Supplies 4 18th July 2009 07:18 PM
Borrowing +/-15V from receiver for pre-amp mattybe Solid State 2 16th April 2009 06:09 AM
+/-15V power to a TI PGA2310. 15V regulators sufficient or do I need adjustable?? nick_g_evans Parts 2 16th July 2008 11:50 AM
Schematics for ClassD amp _world_ Class D 15 17th May 2007 03:05 PM
New classD amp: Gemincore of CL3 vroum90 Class D 37 5th April 2006 09:44 AM


New To Site? Need Help?

All times are GMT. The time now is 06:15 PM.

Page generated in 0.08876 seconds (77.69% PHP - 22.31% MySQL) with 11 queries

Copyright ©1999-2012 diyAudio